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ElenaW [278]
3 years ago
6

why do valence electrons form bonds to create molecules and compounds? A. they are weaker than the electrons found closer to th

e nucleus. B. they are smaller than other electrons. C. they are stronger than the electrons found closer to the nucleus D. They are smaller than other electrons.
Chemistry
2 answers:
Crazy boy [7]3 years ago
7 0

Answer:

grouping pairs

Explanation:

BlackZzzverrR [31]3 years ago
6 0

<u>Answer:</u>

<em>Valence electrons form bonds to create molecules and compounds because they are weaker than the electrons found closer to the nucleus. </em>

<u>Explanation:</u>

Electrons, being negatively charged particles definitely get attracted to the positively charged nucleus. <em>Thus the distance between electrons and nucleus determines the strength of bonding of electrons to the atom. </em>

Valence electrons are present in the outermost shell of the atom and thus the distance between the <em>nucleus and valence electrons is large when compared with the electrons in the inner shells. </em>

In order to form bonds to make molecules and compounds electrons should be weakly bonded to the parent atom. Thus the <em>weak bond with parent atom makes valence electrons the active participants in a chemical reaction. </em>

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Which<br> countries were the world leaders in space exploration throughout the 1960's?
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3 years ago
The thermochemical equation for the reaction of carbon dioxide with sulfur dioxide is shown below. How can the reaction be descr
prisoha [69]

Answer: d. has high activation energy

Activation energy is the energy that a system requires to start a certain process. Also, it <u>is the minimum energy necessary for a given chemical reaction to occur</u>. For a reaction to occur between two molecules, they must collide in the correct orientation and have a minimum amount of energy equal to the activation energy.

As the molecules approach, their electron clouds repel, so energy is required for the collision to occur and therefore the reaction. The activation energy comes from the heat of the system, that is, the translational, vibrational energy, etc. of each molecule. However, if this energy is not enough, the reaction will not be spontaneous.

<u>A reaction between two molecules can be favored by supplying energy to the system.</u> In the case raised in the question, <u>energy equal to 1104 kJ is provided to the system to favor the next reaction </u>

CO2 (g) + 2SO2 (g) → CS2 (g) + 3O2 (g)

<u>Since the energy equal to 1104 kJ is included in the reactants, it can be deduced that it is the energy that is provided to the system for the reaction to occur. </u>However, from the value of this energy it can not be said whether the system is endothermic or exothermic since it is a kinetic variable and the variables of this type do not allow predicting the thermodynamic behavior of a system.

Furthermore, it can be seen that the value of this energy is considerably high, therefore the reaction described has a high activation energy.

3 0
3 years ago
If you can solve both<br> Will mark brainly<br> ASAP
MrRa [10]

Answer:

The main function sis the 2nd one and the substance provides the first 1.

Explanation:

Hope you finish the rest on your own, have fun!

7 0
3 years ago
For the following reaction, 22.0 grams of nitrogen monoxide are allowed to react with 5.80 grams of hydrogen gas . nitrogen mono
mash [69]

NO is the limiting reagent and 4.34 g is the amount of the excess reagent that remains after the reaction is complete

<h3>What is a limiting reagent?</h3>

The reactant that is entirely used up in a reaction is called as limiting reagent.

The reaction:

2NO(g) +2H_2(g) → N_2 +2H_2O

Moles of nitrogen monoxide

Molecular weight: M_(_N_O_)=30g/mol

n_(_N_O_) =\frac{mass}{molar \;mass}

n_(_N_O_) =\frac{22.0}{30g/mol}

n_(_N_O_) = 0.73 mol

Moles of hydrogen

Molecular weight: M_(_H_2_)=30g/mol

n_(_H_2_) =\frac{mass}{molar \;mass}

n_(_H_2_) =\frac{5.80g}{2g/mol}

n_(_H_2_) = 2.9 mol

Hydrogen gas is in excess.

NO is the limiting reagent.

The amount of the excess reagent remains after the reaction is complete.

n_(_N_2_) = (2.9 mol- 0.73 mol NO x \frac{1 \;mol \;of \;H_2}{2 \;mole \;of \;NO}) x \frac{2g \;of \;H_2}{mole \;of \;H_2}

n_(_N_2_) =4.34 g

Learn more about limiting reagents here:

brainly.com/question/26905271

#SPJ1

5 0
1 year ago
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