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Bingel [31]
3 years ago
11

What is the molarity of 4 qof NaCl (MM=58.45) in 3,800 mL of solution?

Chemistry
1 answer:
tiny-mole [99]3 years ago
8 0

Answer:

.018 M

Explanation:

grams/MM=ans./volume(L) = M

4/58.45=ans./3.8=.018 M

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Suppose of barium acetate is dissolved in of a aqueous solution of ammonium sulfate. Calculate the final molarity of barium cati
ollegr [7]

Explanation:

Let us assume that the given data is as follows.

   mass of barium acetate = 2.19 g

   volume = 150 ml = 0.150 L    (as 1 L = 1000 ml)

   concentration of the aqueous solution = 0.10 M

Therefore, the reaction equation will be as follows.

        Ba(C_{2}H_{3}O_{2})_{2} \rightarrow Ba^{2+} + 2C_{2}H_{3}O^{-}_{2}

Hence, moles of C_{2}H_{3}O^{-}_{2} = 2 \times Ba(C_{2}H_{3}O_{2})_{2}  .......... (1)

As,   No. of moles = \frac{mass}{\text{molar mass}}

Hence, moles of Ba(C_{2}H_{3}O_{2})_{2} will be calculated as follows.                          

     No. of moles = \frac{mass}{\text{molar mass}}  

                          =  \frac{2.19 g}{255.415 g/mol}   (molar mass of Ba(C_{2}H_{3}O_{2})_{2} is 255.415 g/mol)            

                       = 8.57 \times 10^{-3}

    Moles of C_{2}H_{3}O^{-}_{2} = 2 \times 8.57 \times 10^{-3}

                          = 0.01715 mol

Hence, final molarity will be as follows.

              Molarity = \frac{\text{no. of moles}}{volume}

                             = \frac{0.01715 mol}{0.150 L}

                             = 0.114 M

Thus, we can conclude that final molarity of barium cation in the solution is 0.114 M.

5 0
3 years ago
Calculate the minimum mass of ammonia needed to produce 396 kg of ammonium sulfate, (NH4)2SO4, and excess sulfuric acid.
Serga [27]

Answer:

2N2H2SO4

Explanation:

this is your answer calculate

5 0
3 years ago
Pls help me 20 points ty
qaws [65]

Answer:

what do you need help with i cant see it

Explanation:

6 0
3 years ago
Read 2 more answers
What is a half-life of an isotope? please help
N76 [4]

Answer:

Explanation:

Hello! Hope this helps!

One important measure of the rate at which a radioactive substance decays is called half-life, or t1/2. Half-life is the amount of time needed for one half of a given quantity of a substance to decay. Half-lives as short as 10–6 second and as long as 109 years are common.

3 0
3 years ago
A 30-g car rolls from a hill 12 cm high and is traveling at 154 cm/s as it travels along a 275 cm horizontal track. What is the
Olegator [25]

Answer:

Explanation:

By definition, the momentum is given by:

p=m*v

Where,

m: car mass

v: speed of the car

Substituting the values in the given definition we have:

p=3*154

Answer:

the momentum of the car is:

4620g * cm/s

8 0
3 years ago
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