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3 years ago

What is the molarity of 4 qof NaCl (MM=58.45) in 3,800 mL of solution?

Chemistry

1 answer:

tiny-mole [99]3 years ago

8 0

Answer:

.018 M

Explanation:

grams/MM=ans./volume(L) = M

4/58.45=ans./3.8=.018 M

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HELP ME PLEASE I BEG YOU

babunello [35]

True I think is the answer

3 0

4 years ago

Consider two different ions. The anion has a valence of -2. The cation has a valence of +2. The two ions are separated by a dist

strojnjashka [21]

Answer:

Force of attraction = 35.96 $\times 10^{27}$ N

Explanation:

Given: charge on anion = -2

Charge on cation = +2

Distance = 1 nm = $10^{-9}$ m

To calculate: Force of attraction.

Solution: The force of attraction is calculated by using equation,

$F = \dfrac{k \times q_1 q_2}{ \r^2}$ ---(1)

where, q represents the charge and the subscripts 1 and 2 represents cation and anion.

k = $8.99 \times 10^9 \ Nm^{2}C^{-2}$

F = force of attraction

r = distance between ions.

Substituting all the values in the equation (1) the equation becomes

$F = \dfrac{8.99 \times 10^9 \times 2 \times 2}{ \left ( 10^-9 \right )^2 }$

Force of attraction = 35.96 $\times 10^{27}$ N

6 0

3 years ago

Question 4 need this answered asap (chemistry)

aleksandrvk [35]

Answer:

Conductivity meter

Explanation:

All of the other choices measure pH and can tell you when the pH changes, which is how you know the neutralization reaction has occurred. A conductivity meter does not measure pH.

3 0

3 years ago

How much heat is required to convert 20.0 g of ice at 50.0⁰C to liquid water at 0.0⁰C? The specific heat of ice is 2.06 J/(g∙⁰C)

Alex777 [14]

Answer:

8740 joules are required to convert 20 grams of ice to liquid water.

Explanation:

The amount of heat required ( $Q$ ), measured in joules, to convert ice at -50.0 ºC to liquid water at 0.0 ºC is the sum of sensible heat associated with ice and latent heat of fussion. That is:

$Q = m\cdot [c\cdot (T_{f}-T_{o})+L_{f}]$ (1)

Where:

$m$ - Mass, measured in grams.

$c$ - Specific heat of ice, measured in joules per gram-degree Celsius.

$T_{o}$ , $T_{f}$ - Temperature, measured in degrees Celsius.

$L_{f}$ - Latent heat of fussion, measured in joules per gram.

If we know that $m = 20\,g$ , $c = 2.06\,\frac{J}{g\cdot ^{\circ}C}$ , $T_{f} = 0\,^{\circ}C$ , $T_{o} = -50\,^{\circ}C$ and $L_{f} = 334\,\frac{J}{g }$ , then the amount of heat is: