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Bingel [31]
3 years ago
11

What is the molarity of 4 qof NaCl (MM=58.45) in 3,800 mL of solution?

Chemistry
1 answer:
tiny-mole [99]3 years ago
8 0

Answer:

.018 M

Explanation:

grams/MM=ans./volume(L) = M

4/58.45=ans./3.8=.018 M

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A solution contains 0.036 M Cu2+ and 0.044 M Fe2+. A solution containing sulfide ions is added to selectively precipitate one of
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Answer:

The precipitate is CuS.

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<u>Step 1: </u>Data given

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Q=Ksp

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<u>For Iron</u>  we have: Ksp=[Fe2+]*[S2-]

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The precipitate is CuS.

Sulfide will precipitate at  [S2-]= 3.61*10^-35 M

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