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LuckyWell [14K]
3 years ago
13

Evaluate 2•4-8 divided by 4

Mathematics
1 answer:
Vaselesa [24]3 years ago
4 0

Answer:

<h2>6.</h2>

Step-by-step explanation:

Answer and work are in picture below.

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How do I answer this dot plot?
Anna11 [10]
It would seem the problem requires you compute the mean, median, and standard deviation of each of the data sets. This is nicely done using the statistics functions of your graphing calculator.

Data Set A (mean, median, standard deviation) = (29.7, 29.5, √12.71)
Data Set B (mean, median, standard deviation) = (27.95, 27, √6.1475)

1. False. Data Set B is skewed to the right.
2. TRUE. 27.95 is within 3 of 29.7.
3. False. √12.71 ≠ √6.1475
4. False. The mean of Data Set A is 29.7.
5. False. Data Set A has the higher standard deviation.
6. TRUE. 29.7 is close to 29.5.

The true statements are
• the 2nd one
• the 6th one
3 0
3 years ago
Una caja de 25 newtons se suspende mediante un cable con diámetro de 2cm¿cuál es el esfuerzo aplicado al cable?
Naddik [55]

El cable experimenta un esfuerzo axial de 79577.472 pascales por el peso de la caja.

<h3>¿Cómo calcular el esfuerzo aplicado sobre el cable?</h3>

La caja tiene masa y está sometida a un campo gravitacional, por tanto, tiene un peso (W), en newtons. Por el principio de acción y reacción (tercera ley de Newton), encontramos que el cable es tensionado debido a ese peso y su área transversal experimenta un esfuerzo axial (σ), en pascales.

Asumiendo una distribución uniforme de la fuerza sobre toda la superficie transversal de la cuerda, tenemos que el esfuerzo axial se calcula mediante la siguiente expresión:

σ = W / (π · D² / 4)

Donde:

  • W - Peso de la caja, en newtons.
  • D - Diámetro del área transversal de la caja, en metros.

Si sabemos que W = 25 N y D = 0.02 m, entonces el esfuerzo axial aplicado a la cuerda es:

σ = 25 N / [π · (0.02 m)² / 4]

σ ≈ 79577.472 Pa

<h3>Observación</h3>

La falta de problemas verificados en español sobre esfuerzos axiales obliga a buscar uno equivalente en inglés.

Para aprender más sobre esfuerzos axiales: brainly.com/question/13683145

#SPJ1

5 0
1 year ago
The product of a + 3 and –2a2 + 15a + 6 is –2a3 + xa2 + 51a + 18. What is the value of x?
geniusboy [140]
Value of x is 9 As when we multiply a + 3 by -2a2 + 15a + 6 We get (a + 3) (-2a2 + 15a + 6) -2a3 + 15a2 + 6a - 6a2 + 45a + 18 -2a3 + 9a2 + 51a + 18 If we compare the coefficients of a2, we get x = 9
8 0
3 years ago
Factoring trinomials<br> Select two for each
iragen [17]

Answer:

1. (x + 3) , (x + 4)

2. (x + 5) , (x - 2)

5 0
3 years ago
Read 2 more answers
A batch of cookies requires 1 1/2 of sugar. How many batches can Ty make with 7 and 1/2 cups of sugar
Leni [432]
1 1/2 = 3/2. 7 1/2 = 15/2

15/2 divided by 3/2 = 5 batches of cookies
8 0
3 years ago
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