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Energy were released from the walnut, q = 1,673.6 J
<h3>Equation :</h3>
To find the energy using formula,
q = mcΔt
where,
q is charge
m is mass
c is specific heat of water
Δt is change in temperature
So, given
t₁ = 50°C
t₂ = 60°C
m = 40g
c = 4.184 J/g
Now putting the values known,
We get,
q = mc(t₂ - t₁)
q = 40g x 4.184 J/g x (60 - 50)
q = 167.36 J x 10
q = 1,673.6 J
<h3>What is heat energy?</h3>
Heat is the thermal energy that is transferred when two systems with different surface temperatures come into contact. Heat is denoted by the letters q or Q and is measured in Joules.
To know more about specific heat :
brainly.com/question/11297584
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Answer:
Energy is added (postive enthalpy)
Explanation:
Ice melting means solid turns into liquid. Solid is more stable than liquid thus you must put in energy to weaken the forces of solid and turn it into liquid. Thus, you must put in energy to melt ice. This makes the enthalpy of the system to be positive.
Answer:
The change in temperature of a coffee cup calorimeter is 8.87°C.
Explanation:
Volume of the water = V = 150 g
Density of the water , d =1.0 g/mL
Mass of the water = M

Mass of solution = m = M = 150.0 g

Moles of NaOH = 
Energy released when 0.125 moles of NaOH added in water = Q

1 kJ = 1000 J
Heat gained by water = Q' = -Q ( conservation of energy)

Specific heat of solution = c = 4.184 J/g°C
Change in temperature of the solution = 



The change in temperature of a coffee cup calorimeter is 8.87°C.