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nekit [7.7K]
3 years ago
13

If Hershey and Chase had used radioactive oxygen in their experiments instead of phosphorus and sulfur, what results would they

have likely obtained?
a. They would have observed a radioactive signal in both the pellet and the liquid.
b. They would have not observed radioactivity anywhere.
c. They would have observed a radioactive signal in the pellet only.
d. They would have observed a radioactive signal in the liquid only.
Chemistry
1 answer:
Pepsi [2]3 years ago
8 0

Answer:

A. They would have observed a radioactive signal in both the pellet and the liquid.

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3 years ago
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Ilia_Sergeevich [38]

27) Partial pressure of oxygen: 57.8 kPa

29) Final volume: 80 mL

30) Final volume: 8987 L

31) Due to property of water of being polar, ice floats on water

Explanation:

27)

In a mixture of gases, the total pressure of the mixture is the sum of the partial pressures:

p_T = p_1 + p_2 + ... + p_N

In this problem, the mixture contains 3 gases (helium, carbon dioxide and oxygen). We know that the total pressure is

p_T=201.4 kPa

We also know the partial pressures of helium and carbon dioxide:

P_{He}=125.4 kPa\\P_{CO_2}=18.2 kPa

The total pressure can be written as

p_T=p_{He}+p_{CO_2}+p_{O_2}

where p_{O_2} is the partial pressure of oxygen. Therefore, we find

p_{O_2}=p_T-p_{He}-p_{CO_2}=201.4-125.4-18.2=57.8 kPa

29)

Assuming that the pressure of the gas is constant, we can apply Charle's law, which states that:

"For an ideal gas at constant pressure, the volume of the gas is proportional to its absolute temperature"

Mathematically,

\frac{V}{T}=const.

where

V is the volume of the gas

T is the Kelvin temperature

We can re-write it as

\frac{V_1}{T_1}=\frac{V_2}{T_2}

Here we have:

V_1 = 42 mL (initial volume)

T_1=-89^{\circ}C+273=184 K is the initial temperature

T_2=77^{\circ}C+273=350 K is the final temperature

Solving for V2, we find the final volume:

V_2=\frac{V_1 T_2}{T_1}=\frac{(42)(350)}{184}=80 mL

30)

For this problem, we can use the equation of state for ideal gases, which can be written as

\frac{p_1 V_1}{T_1}=\frac{p_2 V_2}{T_2}

where in this problem:

p_1 = 102.3 kPa is the initial pressure

V_1=1975 L is the initial volume

T_1=25^{\circ}C+273=298 K is the initial temperature

p_2=21.5 kPa is the final pressure

T_2=12^{\circ}C+273=285 K is the final temperature

And solving for V2, we find the final volume of the balloon:

V_2=\frac{p_1 V_1 T_2}{p_2 T_1}=\frac{(102.3)(1975)(285)}{(21.5)(298)}=8987 L

31)

A molecule of water consists of two atoms hydrogen bond with an atom of oxygen (H_2 O) in a covalent bond.

While the molecul of water is overall neutral, due to the higher electronegativity of the oxygen atom, electrons are slightly shifted towards the oxygen atom; as a result, there is a slightly positive charge on the hydrogen side, and a slightly negative charge on the oxygen side (so, the molecules is said to be polar).

As a consequence, molecules of water attract each other, forming the so-called "hydrogen bonds".

One direct consequence of the polarity of water is that ice floats on liquid water.

Normally, for every substance on Earth, the solid state is more dense than the liquid state. However, this is not true for water, because ice is less dense than liquid water.

This is due to the polarity of water. In fact, when the temperature of water is decreased to freezing point and water becomes ice, the hydrogen bondings "force" the molecules to arrange in a lattice structure, so that the molecules become more spaced when they turn into solid state. As a result, ice occupies more volume than water, and therefore it is less dense, being able to float on water.

Learn more about ideal gases:

brainly.com/question/9321544

brainly.com/question/7316997

brainly.com/question/3658563

#LearnwithBrainly

4 0
3 years ago
A 0.10 M solution of Na2HPO4 could be made a buffer solution with all of the following EXCEPT ________.NaH2PO4K3PO4Na3PO4H3PO4
Kipish [7]

The answer is: H₃PO₄.

A phosphoric acid is three protic acid, which means that in water release tree protons.

Phosphoric acid ionizes in three steps in water.

First step: H₃PO₄(aq) ⇄ H₂PO₄⁻(aq) + H⁺(aq).

Second step: H₂PO₄⁻(aq)⇄ HPO₄²⁻(aq) + H⁺(aq).

Third step: HPO₄²⁻(aq) ⇄ PO₄³⁻(aq) + H⁺(aq).

Species that are present: H₃PO₄, H₂PO₄⁻, HPO₄²⁻, PO₄³⁻ and H⁺.

A buffer can be defined as a substance that prevents the pH of a solution from changing by either releasing or absorbing H⁺ in a solution.

Buffer is a solution that can resist pH change upon the addition of an acidic or basic components and it is able to neutralize small amounts of added acid or base, pH of the solution is relatively stable.

7 0
3 years ago
Consider the reaction. PCl5(g)↽−−⇀PCl3(g)+Cl2(g) K=0.042 The concentrations of the products at equilibrium are [PCl3]=0.18 M and
tatyana61 [14]

<u>Answer:</u> The equilibrium concentration of PCl_5 is 1.285 M.

<u>Explanation:</u>

The chemical equation for the decomposition of phosphorus pentachloride follows:

PCl_5(g)\rightleftharpoons PCl_3(g)+Cl_2(g)

The expression for equilibrium constant is given as:

K_c=\frac{[PCl_3][Cl_2]}{[PCl_5]}

We are given:

K_c=0.042

[PCl_3]=0.18M

[Cl_2]=0.30M

The concentration of solid substances are taken to be 1. Thus, they do not appear in the equilibrium constant expression.

Putting values in above equation, we get:

0.042=\frac{0.18\times 0.30}{[PCl_5]}

[PCl_5]=1.285

Hence, the equilibrium concentration of PCl_5 is 1.285 M.

6 0
3 years ago
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Hoochie [10]
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5 0
3 years ago
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