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Marat540 [252]
4 years ago
6

A pizza from cheap pizza with a 6 inch radius costs $3.00. write a direct variation equation to represent how much a pizza with

a 1 inch radius would cost?
Mathematics
1 answer:
Eva8 [605]4 years ago
7 0

Answer:

Cost of Pizza for 1 inch radius is $0.5.

The Direct variation between cost of pizza and radius in inches of pizza is C= 0.5r

Step-by-step explanation:

Given:

Cost of 6 inch pizza = $3.00

We need to find the direct variation equation to represent cost of pizza with a 1 inch radius.

Let Cost f Pizza be represented by 'C'.

Also radius in inches of pizza be represented by 'r'.

First we will find Cost of pizza for 1 inch radius.

Now 6 inch pizza = $3.00

So 1 inch Pizza = Cost of pizza for 1 inch radius.

By Using Unitary method we get;

Cost of pizza for 1 inch radius = \frac{3}{6} = \$0.5

Cost of Pizza for 1 inch radius is $0.5.

Hence We can say the direct variation would be given as;

C= 0.5r

Hence The Direct variation between cost of pizza and radius in inches of pizza is C= 0.5r

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The IQR is 42.5

Step-by-step explanation:

Interquartile range is the difference of third and first quartile.

First of all we have to find the median for that purpose the data has to be arranged in ascending order. The data is already in ascending order.

As the number of values are odd

n=21

The median will be: (\frac{n+1}{2}) th\ term

Putting n=21

(\frac{21+1}{2})th\ term\\=(\frac{22}{2})th\ term\\= 11th\ term

The 11th term is 133

So median = 133

Now the data is divided into two halves

One is: 98, 100, 101, 102, 108, 109, 111,118, 129, 132

2nd is: 135, 135, 145, 146, 146, 156, 170 176, 180, 180

Q1 will be the median of first half and Q3 will be the median of 2nd half.

As now the halves contain even number of values, the medians will be the average of middle two values

<u>For First Half:</u>

98, 100, 101, 102, <u>108, 109</u>, 111,118, 129, 132

Q_1 = \frac{108+109}{2}\\Q_1 = \frac{217}{2}\\Q_1 = 108.5

<u>For Second Half:</u>

135, 135, 145, 146, 146, 156, 170 176, 180, 180

Q_2 = \frac{146+156}{2}\\Q_2 = \frac{302}{2}\\Q_2 = 151

Now

<u>Interquartile Range:</u>

IQR = Q_3-Q_1\\= 151-108.5\\=42.5

Hence,

The IQR is 42.5

Keywords: Median, IQR

Learn more about median at:

  • brainly.com/question/10940255
  • brainly.com/question/10941043

#LearnwithBrianly

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