The molality of a solute is equal to the moles of solute per kg of solvent. We are given the mole fraction of I₂ in CH₂Cl₂ is <em>X</em> = 0.115. If we can an arbitrary sample of 1 mole of solution, we will have:
0.115 mol I₂
1 - 0.115 = 0.885 mol CH₂Cl₂
We need moles of solute, which we have, and must convert our moles of solvent to kg:
0.885 mol x 84.93 g/mol = 75.2 g CH₂Cl₂ x 1 kg/1000g = 0.0752 kg CH₂Cl₂
We can now calculate the molality:
m = 0.115 mol I₂/0.0752 kg CH₂Cl₂
m = 1.53 mol I₂/kg CH₂Cl₂
The molality of the iodine solution is 1.53.
Answer:
[2 ]Na+[2 ]H2O -> [ 2] NaOH + [1]H2
Answer:
Iron
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Answer:
B. ethylamine.
Explanation:
- Since the compound contains NH₂, it is an amine compound.
- The alkyl group C₂H₅- contains 2 C atoms (ethyl group).
<em>So, the compound is ethylamine.</em>
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Answer:
B
Explanation:
All elements on both sides of the equation have the same amount of moles
