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hoa [83]
3 years ago
11

What is the electrical charge of an anion?

Chemistry
2 answers:
Greeley [361]3 years ago
6 0
A cation is a positively charged ion.
An anion is a negatively charged ion.
If it's neutral, it's just an ion.
BartSMP [9]3 years ago
5 0
B would be the answer
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How many atoms are in 1.0 formula units of magnesium acetate?
Ray Of Light [21]

Answer:

15

Explanation:

Magnesium Acetate Mg(C2H3O2)2

Number of atoms:

Carbon = 4

Hydrogen = 6

Magnesium = 1

Oxygen = 4

Total = 15

7 0
3 years ago
What is the molar mass of the imaginary compound Z(AX3)2
astra-53 [7]

The molar mass of the imaginary compound Z(AX₃)₂ is the sum of the molar mass of Z, A and X.

<h3>How do we calculate molar mass?</h3>

Molar mass of any compound will be calculated by adding the mass of each atoms present in that compound.

Given compound is Z(AX₃)₂, molar mass of the given compound will be calculated as:

Molar mass of Z(AX₃)₂ = Molar mass of Z + molar mass of 2(A) + molar mass of 6(X)

Hence molar mass of Z(AX₃)₂ is the sum of the masses of all atoms.

To know more about molar mass, visit the below link:

brainly.com/question/18983376

#SPJ1

7 0
2 years ago
The activation energy of an uncatalyzed reaction is 70 kJ/mol. When a catalyst is added, the activation energy (at 20 °C) is 42
denis23 [38]

Answer:

T = 215.33 °C

Explanation:

The activation energy is given by the Arrhenius equation:

k = Ae^{\frac{-Ea}{RT}}

<u>Where:</u>

k: is the rate constant

A: is the frequency factor    

Ea: is the activation energy

R: is the gas constant = 8.314 J/(K*mol)

T: is the temperature

We have for the uncatalyzed reaction:

Ea₁ = 70 kJ/mol

And for the catalyzed reaction:

Ea₂ = 42 kJ/mol

T₂ = 20 °C = 293 K

The frequency factor A is constant and the initial concentrations are the same.

Since the rate of the uncatalyzed reaction (k₁) is equal to the rate of the catalyzed reaction (k₂), we have:

k_{1} = k_{2}

Ae^{\frac{-Ea_{1}}{RT_{1}}} = Ae^{\frac{-Ea_{2}}{RT_{2}}}   (1)

By solving equation (1) for T₁ we have:

T_{1} = \frac{T_{2}*Ea_{1}}{Ea_{2}} = \frac{293 K*70 kJ/mol}{42 kJ/mol} = 488. 33 K = 215.33 ^\circ C  

Therefore, we need to heat the solution at 215.33 °C so that the rate of the uncatalyzed reaction is equal to the rate of the catalyzed reaction.

I hope it helps you!      

4 0
3 years ago
I will give BRAINIEst please!!! help meeee omg
Alexxandr [17]

Answer:

(a)57.48 percent (b) 29.45 percent

Explanation:

copper(II) bromide is 29.45 percent copper and 71.54 percent bromine. so the first element percentage composition is always the percentage composition of the compound.

that goes same with sodium hydroxide. it  is 57.48 percent sodium, 40 percent oxygen, and 2.52 percent hydrogen.

4 0
3 years ago
Select all that apply.
stich3 [128]

Answer:

air pollution and potential reactor accidents

Explanation:

i pretty sure on those two

4 0
2 years ago
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