Balance Chemical Equation is,
<span>CaO </span>₍s₎ <span>+ CO</span>₂ ₍g₎ <span>→ CaCO</span>₃ ₍s₎
According to Equation
56.07 g of CaO when reacted with excess CO₂ produces = 100.08 g of CaCO₃.
Then,
1.8 g of CaO is reacted with excess CO₂ = X g of CaCO₃ will produce.
Solving for X,
X = (100.08 g × 1.8 g) ÷ 56. 07 g
X = 3.21 g of CaCO₃
Answer:
100mL of chloromethane
Explanation:
Based on the equation:
Cl₂(g) + CH₄(g) → HCl(g) + CH₃Cl(g)
<em>1 mole of chlorine reacts per mole of methane to produce 1 mole of HCl and 1 mole of chloromethane</em>
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Avogadro's law says that equal volumes of all gases, at the same temperature and pressure, have the same number of molecules. Using Avogadro's law we can say of the equation that:
<em>1 mL of chlorine reacts per mL of methane to produce 1 mL of HCl and 1 mL of chloromethane</em>
Because the system stays under constant pressure and temperature.
As 100mL of Cl₂ reacts with excess of CH₄ and 1mL of Cl₂ produce 1mL of CH₃Cl there are produced:
<h3>100mL of chloromethane</h3>
Answer:
28 g/mol, N2
Explanation:
Given data:
Volume of gas = 5.0 L
Mass of gas = 6.3 g
Pressure = 1 atm
Temperature = 273 K
Molar mass of gas = ?
Solution:
We will calculate the density first.
d = mass/ volume
d = 6.3 g/ 5.0 L
d = 1.26 g/L
Molar mass:
d = PM/RT
M = dRT/P
M = 1.26 g/L× 0.0821 atm.L/mol.K × 273 K/ 1 atm
M = 28 g/mol
Molar mass of N₂ is 28 g/mol thus given gas is N₂.
The C=O stretch appears as a very sharp and intense peak in an IR spectrum. Since, C=O is a double bond, it appears in the "double bond" region of the IR spectrum, which is typically in the 1500-2000 cm-1 range. More specifically, C=O generally falls in the range of 1650-1850 cm-1. The reason for the range is that there are many types of functional groups that contain a carbonyl (C=O), such as a ketone, aldehyde, amide, or ester. Each of these will have a slightly different value as each stretch will have a different energy due to various factors such as conjugation.