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stealth61 [152]
3 years ago
7

MARKING BRAINLIEST!! - Chlorine reacts with methane to form gaseous hydrogen chloride and chloromethane according to the followi

ng equation: Cl2 (g) + CH4 (g) → HCl (g) + CH3Cl (g) If 100 mL of chlorine reacted with excess methane at constant pressure and temperature, what volume of chloromethane would be formed? Question 7 options: 50, cannot tell from the information provided, 200, 100
Chemistry
1 answer:
WARRIOR [948]3 years ago
7 0

Answer:

100mL of chloromethane

Explanation:

Based on the equation:

Cl₂(g) + CH₄(g) → HCl(g) + CH₃Cl(g)

<em>1 mole of chlorine reacts per mole of methane to produce 1 mole of HCl and 1 mole of chloromethane</em>

<em />

Avogadro's law says that equal volumes of all gases, at the same temperature and pressure, have the same number of molecules. Using Avogadro's law we can say of the equation that:

<em>1 mL of chlorine reacts per mL of methane to produce 1 mL of HCl and 1 mL of chloromethane</em>

Because the system stays under constant pressure and temperature.

As 100mL of Cl₂ reacts with excess of CH₄ and 1mL of Cl₂ produce 1mL of CH₃Cl there are produced:

<h3>100mL of chloromethane</h3>
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