Question

MARKING BRAINLIEST!! - Chlorine reacts with methane to form gaseous hydrogen chloride and chloromethane according to the following equation: Cl2 (g) + CH4 (g) → HCl (g) + CH3Cl (g) If 100 mL of chlorine reacted with excess methane at constant pressure and temperature, what volume of chloromethane would be formed? Question 7 options: 50, cannot tell from the information provided, 200, 100

Answer 1

Answer:

100mL of chloromethane

Explanation:

Based on the equation:

Cl₂(g) + CH₄(g) → HCl(g) + CH₃Cl(g)

1 mole of chlorine reacts per mole of methane to produce 1 mole of HCl and 1 mole of chloromethane

Avogadro's law says that equal volumes of all gases, at the same temperature and pressure, have the same number of molecules. Using Avogadro's law we can say of the equation that:

1 mL of chlorine reacts per mL of methane to produce 1 mL of HCl and 1 mL of chloromethane

Because the system stays under constant pressure and temperature.

As 100mL of Cl₂ reacts with excess of CH₄ and 1mL of Cl₂ produce 1mL of CH₃Cl there are produced:

100mL of chloromethane