Answer: scalene and obtuse
Justification:
You can find the angles using the law of cosine:
c^2 = a^2 + b^2 - 2abcos(γ)
=> cos(γ) = [a^2 + b^2 - c^2] / (2ab)
1) cos(γ) = [10^2 + 11^2 - 15^2] / (2*10*11) = - 0.0181818
=> γ = arccos(-0.0181818} ≈ 91°
2) cos(α) = [b^2 + c^2 - a^2 ] / 2bc = [11^2 + 15^2 - 10^2] / (2*11*15] = 0.7454545
=> α = arccos(0.7454545) ≈ 41.8°
3) cos(β) = [a^2 + c^2 - b^2] / (2ac) = [10^2 + 15^2 - 11^2] /(2*10*15) = 0.68
=> β = arccos(0.68) ≈ 47.2°
4) Verification: 91° + 41.8° + 47.2° = 180°
5) The triangles with the three different sides are called scalenes (which you can tell with only the measures of the sides).
6) The triangles with one angle greater than 90° are called obtuse.
So, the triangle is scalene and obtuse.
It would be 70*35 / 100 + 30*25 / 100
2450 /100 + 750/100
24.50 + 7.50 = 32
So, your answer is $32
Answer:
d = 10/72
Step-by-step explanation:
c and d vary inversely
c = k/d
Where,
k = constant of proportionality
d = 2/9 when c = 5
c = k/d
5 = k ÷ 2/9
5 = k × 9/2
5 = 9k/2
Cross product
5*2 = 9k
10 = 9k
k = 10/9
c = k/d
c = 10/9 ÷ d
c = 10/9 × 1/d
c = 10/9d
find d when c = 8
c = 10/9d
8 = 10/9d
Cross product
8*9d = 10
72d = 10
d = 10/72
Answer:
20.3
Step-by-step explanation:
I don’t now what the answer is sorry I will try and figure it
