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Cloud [144]
3 years ago
12

Suppose that Paul D. Trigger fires a bullet from a gun. Will the speed of the bullet leaving the muzzle will be the same as the

speed of the recoiling gun? Explain.
Physics
1 answer:
Y_Kistochka [10]3 years ago
6 0

Answer:

Explanation:

The speed of the bullet will only be the same if the mass of the bullet is equal to the mass of the gun. This because only their momentum ( product of mass and velocity) is conserved; the momentum before the gun and pullet was fired is equal to the momentum of the recoil of the gun and the momentum of the released bullet. The smallest mass  receives the highest speed (the bullet) while the larger mass ( the gun) receives the lowest speed ( speed of recoil).

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What happens with the plates at this Juan de fuca
djverab [1.8K]

Answer:

Subduction of the Juan de Fuca plate causes melting and magma generation in the mantle which rises to the surface to create the Cascade volcanoes.

Explanation:

8 0
3 years ago
What is meant by the statement '' density of water is 1000 kilograms per cubic metre ''?
LenKa [72]
It means that if you had a cubic meter of water it would weigh 1000 kilograms
4 0
3 years ago
Suppose the odometer on our car is broken and we want to estimate the distance driven over a 30 second time interval. We take th
Natalija [7]

Let say for every 5 s of time interval the speed will remain constant

so it is given as

v(mi/h)   16    21    23    26    33    30     28

now we have to convert the speed into ft/s as it is given that 1 mi/h = 5280/3600 ft/s

so here we will have

v(ft/s)      23.5    30.8     33.73     38.13     48.4     44     41.1

now for each interval of 5 s we will have to find the distance cover for above interval of time

d = v \times t

d = (23.5 + 30.8 + 33.73 + 38.13 + 48.4 + 44 + 41.1) \times 5

d = 1298.1 ft

so here it will cover 1298.1 ft distance in 30 s interval of time

4 0
3 years ago
Read 2 more answers
A motorcycle traveling at a speed of 44.0 mi/h needs a minimum of 44.0 ft to stop. If the same motorcycle is traveling 79.0 mi/h
Tasya [4]

Answer:

141.78 ft

Explanation:

When speed, u = 44mi/h, minimum stopping distance, s = 44 ft = 0.00833 mi.

Calculating the acceleration using one of Newton's equations of motion:

v^2 = u^2 + 2as\\\\v = 0 mi/h\\\\u = 44 mi/h\\\\s = 0.00833 mi\\\\=> 0^2 = 44^2 + 2 * a * 0.00833\\\\=> 1936 = -0.01666a\\\\a = -116206.48 mi/h^2 or -14.43 m/s^2

Note: The negative sign denotes deceleration.

When speed, v = 79mi/h, the acceleration is equal to when it is 44mi/h i.e. -116206.48 mi/h^2

Hence, we can find the minimum stopping distance using:

v^2 = u^2 + 2as\\\\v = 0 mi/h\\\\u = 79 mi/h\\\\a = -116206.48 mi/h\\\\=> 0^2 = 79^2 + (2 * -116206.48 * s)\\\\6241 = 232412.96s\\\\s = \frac{6241}{232412.96} \\\\s = 0.0268531 mi = 141.78 ft

The minimum stopping distance is 141.78 ft.

4 0
3 years ago
A party shop delivers helium-filled balloons to homes and businesses. The owners realize from experience that on hot summer days
kvasek [131]

Answer:As the temperature increases, the helium in the ballon expands.

Explanation:

I took the quiz already

6 0
2 years ago
Read 2 more answers
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