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Cloud [144]
4 years ago
12

Suppose that Paul D. Trigger fires a bullet from a gun. Will the speed of the bullet leaving the muzzle will be the same as the

speed of the recoiling gun? Explain.
Physics
1 answer:
Y_Kistochka [10]4 years ago
6 0

Answer:

Explanation:

The speed of the bullet will only be the same if the mass of the bullet is equal to the mass of the gun. This because only their momentum ( product of mass and velocity) is conserved; the momentum before the gun and pullet was fired is equal to the momentum of the recoil of the gun and the momentum of the released bullet. The smallest mass  receives the highest speed (the bullet) while the larger mass ( the gun) receives the lowest speed ( speed of recoil).

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atom

Explanation:

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4 years ago
Which two pieces of data indicate that Uranus resides in the outer region of the solar system
LuckyWell [14K]

Answer:

Our solar system has total eight planets out of which four are inner planets and four are outer planets. The four outer planets are Jupiter, Saturn, Uranus and Neptune. The common characteristics of outer planets is that they are gaseous planets. They are larger on size than the inner rocky planets and are faraway from Sun. They have larger period of revolution around the Sun.

Uranus is a gaseous planet and lies far from Sun and hence has large period of revolution. It takes 84 Earth years to revolve around Sun. This data indicates that Uranus resides in the outer region of the Solar System.

4 0
4 years ago
Economics is the study of producing and ____ goods and services.
user100 [1]

Economics is the study of producing and consuming goods and services.

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3 0
4 years ago
Read 2 more answers
alayn h uderstands the half life of a certain substance is 90days. how long would it take for 80lbs of her substance to be reduc
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7 0
3 years ago
A block (mass m1) lying on a frictionless inclined plane is connected to a mass (mass m2) by a massless cord passing over a pull
azamat

Answer:

a) System aceleration:

  • a=\frac{g(m_2-m_1sin(\theta))}{m_1+m_2}

b) Direction of movement:

The block m_1 down the plane when the acceleration is negative. This occur when:

m_2-m_1sin(\theta)

The block m_2 up the plane when the acceleration is positive. This occur when:

m_2-m_1sin(\theta)>0

Explanation:

For the block m_1 the move direction is parallel (||) to the plane

\sum F_{||}=m_1a=T-sin(\theta)mg  (1)

For the block m_2  the move direction is vertical (y)

\sum F_y=m_2a=m_2g-T  (2)

Both blocks are connected with the same cable, therefore, the tension on the cable and the acceleration is the same for both.

Solving the equation 2 for T:

T=m_2g-m_2a   (3)

replacing (3) in the equation (1)

m_2g-m_2a- m_1gsin(\theta)=m_1a  (4)

solving (4) for a:

a=\frac{g(m_2-m_1sin(\theta))}{m_1+m_2}

8 0
3 years ago
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