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Cloud [144]
4 years ago
12

Suppose that Paul D. Trigger fires a bullet from a gun. Will the speed of the bullet leaving the muzzle will be the same as the

speed of the recoiling gun? Explain.
Physics
1 answer:
Y_Kistochka [10]4 years ago
6 0

Answer:

Explanation:

The speed of the bullet will only be the same if the mass of the bullet is equal to the mass of the gun. This because only their momentum ( product of mass and velocity) is conserved; the momentum before the gun and pullet was fired is equal to the momentum of the recoil of the gun and the momentum of the released bullet. The smallest mass  receives the highest speed (the bullet) while the larger mass ( the gun) receives the lowest speed ( speed of recoil).

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shutvik [7]

Answer:

C

Explanation:

Earthquake s are subducting the ancient early rocks

4 0
3 years ago
Read 2 more answers
One model for a certain planet has a core of radius R and mass M surrounded by an outer shell of inner radius R, outer radius 2R
Drupady [299]

(a) 120.8 m/s^2

The gravitational acceleration at a generic distance r from the centre of the planet is

g=\frac{GM'}{r^2}

where

G is the gravitational constant

M' is the mass enclosed by the spherical surface of radius r

r is the distance from the centre

For this part of the problem,

r=R=1.17\cdot 10^6 m

so the mass enclosed is just the mass of the core:

M'=M=2.48\cdot 10^{24}kg

So the gravitational acceleration is

g=\frac{(6.67\cdot 10^{-11})(2.48\cdot 10^{24}kg)}{(1.17\cdot 10^6 m)^2}=120.8 m/s^2

(b) 67.1 m/s^2

In this part of the problem,

r=3R=3(1.17\cdot 10^6 m)=3.51\cdot 10^6 m

and the mass enclosed here is the sum of the mass of the core and the mass of the shell, so

M'=M+4M=5M=5(2.48\cdot 10^{24}kg)=1.24\cdot 10^{25}kg

so the gravitational acceleration is

g=\frac{(6.67\cdot 10^{-11})(1.24\cdot 10^{25}kg)}{(3.51\cdot 10^6 m)^2}=67.1 m/s^2

8 0
4 years ago
A 60 [Hz] high-voltagepower line carries a current of 1000 [A]. The power line is at a height of 50 [m] above the earth. What is
omeli [17]

Answer:

The magnitude of the magneticfield B[T] at a point on the surface of the earth directly below the power line is B=1.496x10^(-6) T.

Explanation:

The distance from the wire to a point in the surface is the heigth of the wire.

The formula for the magnetic field on any point at distance R from a wire conducting alternating current is:

B=\frac{\mu_0I}{2\pi R} =\frac{(4\pi\cdot 10^{-7}T\cdot m/A)(1000\,A)}{2\pi \cdot 50\,m} =1.496\cdot10^{-6}\,T

4 0
3 years ago
The term used for showing the amount of electricity that is flowing is called ___________.
Neporo4naja [7]

Amp??? I am not to sure but I think that it is correct

5 0
3 years ago
The scientific principle which explains the observation that the amount of heat transfer accompanying a change in one direction
Sphinxa [80]

Answer:

The Law of the Conservation of Energy

Explanation:

The Energy Conservation Act tells us that any form of energy changes from one form to another. And that you can never have a higher amount of energy than you originally got. That is, if you have 100 [J] of energy to be transferred as heat from one medium to another, only 100 [J] can be used to be transferred, no amount greater than this value can be transferred.

The particular study of Energy Transfer in the form of heat is important in sciences such as thermodynamics and heat transfer.

4 0
3 years ago
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