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Flura [38]
2 years ago
14

A train travels from the bottom of a hill to the top of a hill, its moves slower by the time it reaches the top is an example of

____. A. positive acceleration B. velocity C. negative acceleration D. speed
Physics
2 answers:
Neko [114]2 years ago
5 0
The answer is letter C. <span>A train travels from the bottom of a hill to the top of a hill, its moves slower by the time it reaches the top is an example of negative acceleration.

In physics, acceleration can be described as an objects change of velocity. When an object gains velocity, it is positive acceleration, and negative acceleration for the opposite.

</span>

Thank you for posting your question. I hope you found what you were after. Please feel free to ask me more.

<span> </span>

hjlf2 years ago
5 0
<span>Negative Acceleration is when the acceleration of an object slows down, like throwing something in the air. It will get slower going up, and then it will stop, that is the negative acceleration, and then the object will come back down, and will speed up, which is positive acceleration.
</span>
A train travels from the bottom of a hill to the top of a hill, its moves slower by the time it reaches the top is an example of <span>negative acceleration.
Best Choice : </span><span> C. negative acceleration</span>

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A bogie is one more stroke over par true or false in footgolf
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Answer:

True

Explanation:

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5 0
2 years ago
Electric fish generate current with biological cells called electroplaques, which are physiological emf devices. The electroplaq
Harlamova29_29 [7]

Answer:

current in water = 0.924 A

Explanation:

Let the current in each row be i.

Thus, current in water is contributed by each row and total current in water becomes 140i.

We are given;

emf of each electroplaque = 0.15 V

Number of electroplaques = 5000

internal resistance = 0.25 Ω

resistance = 800Ω

Applying Kirchoff's Voltage Law to row and water, we have;

5000E − (5000r)i − 800(140i) = 0

Rearranging;

5000E = (5000r)i + 800(140i)

Plugging in the relevant values;

5000 x 0.15 = i((5000 x 0.25) + 112,000)

750 = 113,250i

i = 750/113,250

i = 0.0066 A

Recall earlier, the current in water is 140i.

Thus, current in water = 140 x 0.0066

= 0.924

5 0
2 years ago
A 10 kg monkey climbs up a massless rope that runs over a frictionless tree limb and back down to a 15 kg package on the ground.
pshichka [43]

Answer:

A. 4,9 m/s2

B. 2,0 m/s2

C. 120 N

Explanation:

In the image, 1 is going to represent the monkey and 2 is going to be the package.  Let a_mín be the minimum acceleration that the monkey should have in the upward direction, so the package is barely lifted. Apply Newton’s second law of motion:

\sum F_y=m_1*a_m_i_n = T-m_1*g

If the package is barely lifted, that means that T=m_2*g; then:

\sum F_y =m_1*a_m_i_n=m_2*g-m_1*g

Solving the equation for a_mín, we have:

a_m_i_n=((m_2-m_1)/m_1)*g = ((15kg-10kg)/10kg)*9,8 m/s^2 =4,9 m/s^2

Once the monkey stops its climb and holds onto the rope, we set the equation of Newton’s second law as it follows:

For the monkey: \sum F_y = m_1*a \rightarrow T-m_1*g=m_1*a

For the package: \sum F_y = m_2*a \rightarrow m_2*g - T = m_2*a

The acceleration a is the same for both monkey and package, but have opposite directions, this means that when the monkey accelerates upwards, the package does it downwards and vice versa. Therefore, the acceleration a on the equation for the package is negative; however, if we invert the signs on the sum of forces, it has the same effect. To be clearer:

For the package: \sum F_y = -m_2*a \rightarrow T-m2*g=-m_2*a \rightarrow m_2*g -T=m_2 *a

We have two unknowns and two equations, so we can proceed. We can match both tensions and have:

m_1*a+m_1*g=m_2*g-m_2*a

Solving a, we have

(m_1+m_2)*a =(m_2 - m1)*g\\\\a=((m_2-m_1)/(m_1+m_2))*g \rightarrow a=((15kg-10kg)/(10kg+15kg))*9,8 m/s^2\\\\a= 2,0 m/s^2

We can then replace this value of a in one for the sums of force and find the tension T:

T = m_1*a+m_1*g \rightarrow T=m_1*(a+g)\\\\T = 10kg*(2,0 m/s^2+9,8 m/s^2) \\\\T = 120 N

5 0
3 years ago
LABORATORY TITLE:
mezya [45]

Answer:

PAPER CLIPS ON NOSE OF A PAPER AIRPLANE

Purpose: To determine if the number of paperclips on the nose of a paper airplane affects the velocity and speed, measured in meters per seconds.

Make a Hypothesis Based on the Learning Thus Far: If the number of paperclips on the nose of a paper airplane increases, then the speed will _increase______ (increase, decrease, stay the same) in a __linear_______ (linear, exponential, logarithmic) mathematical relationship, and the velocity will (increase, decrease, stay the same) in a __exponential____ (linear, exponential, logarithmic) mathematical relationship. (Fill in the appropriate words for your hypothesis.)

Pictures: Insert at least 3 pictures of yourself conducting the experiment into this lab report. At least 2 pictures must show your face as you conduct the investigation. You may need to ask someone to help take these photos.

Explanation:

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3 years ago
a current of 180 mini amphere passes through a conductor for 5minute calculate the quantity of electricity transported​
oksano4ka [1.4K]

Answer:

Explanation:

You can calculate the total electric charge that passes through the conductor as q=It=(180\times 10^{-3})(5\times 60)= 54 C. It means that the number of electron that passes through the conductor is:

n=\frac{q}{e}=\frac{54}{1.6\times 10^{-19}}=33.75\times 10^{19}

8 0
2 years ago
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