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Flura [38]
3 years ago
14

A train travels from the bottom of a hill to the top of a hill, its moves slower by the time it reaches the top is an example of

____. A. positive acceleration B. velocity C. negative acceleration D. speed
Physics
2 answers:
Neko [114]3 years ago
5 0
The answer is letter C. <span>A train travels from the bottom of a hill to the top of a hill, its moves slower by the time it reaches the top is an example of negative acceleration.

In physics, acceleration can be described as an objects change of velocity. When an object gains velocity, it is positive acceleration, and negative acceleration for the opposite.

</span>

Thank you for posting your question. I hope you found what you were after. Please feel free to ask me more.

<span> </span>

hjlf3 years ago
5 0
<span>Negative Acceleration is when the acceleration of an object slows down, like throwing something in the air. It will get slower going up, and then it will stop, that is the negative acceleration, and then the object will come back down, and will speed up, which is positive acceleration.
</span>
A train travels from the bottom of a hill to the top of a hill, its moves slower by the time it reaches the top is an example of <span>negative acceleration.
Best Choice : </span><span> C. negative acceleration</span>

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Answer the following question according to formal grammatical rules.
VARVARA [1.3K]

Answer:

c

Explanation:

just trying to follow basic grammar.

5 0
3 years ago
You have two square metal plates with side lengths of (6.50 C) cm. You want to make a parallel-plate capacitor that will hold a
gtnhenbr [62]

Answer:

The necessary separation between  the two parallel plates is 0.104 mm

Explanation:

Given;

length of each side of the square plate, L = 6.5 cm = 0.065 m

charge on each plate, Q = 12.5 nC

potential difference across the plates, V = 34.8 V

Potential difference across parallel plates is given as;

V = \frac{Qd}{L^2 \epsilon_o} \\\\d = \frac{V L^2 \epsilon_o}{Q}

Where;

d is the separation or distance between the two parallel plates;

d = \frac{VL^2 \epsilon_o}{Q} \\\\d =  \frac{34.8*(0.065)^2 *8.854*10^{-12}}{12.5*10^{-9}} \\\\d = 0.000104 \ m\\\\d = 0.104 \ mm

Therefore, the necessary separation between  the two parallel plates is 0.104 mm

6 0
3 years ago
The reservoir stores 6 500 000 m3 of water. The density of the water is 998 kg/m3. Calculate the mass of water in the reservoir.
Mekhanik [1.2K]

Answer:

Mass = 64,870,000,000 kilograms

Explanation:

Given the following data;

Density = 998 kg/m³

Volume = 6,500,000 m³

To find the mass of water in the reservoir;

Density can be defined as mass all over the volume of an object.

Simply stated, density is mass per unit volume of an object.

Mathematically, density is given by the equation;

Density = mass/volume

Making mass the subject of formula, we have;

Mass = density * volume

Mass = 998 * 6,500,000

Mass = 64,870,000,000 kilograms

8 0
3 years ago
What is amplitude, wavelength, and frequency?
krek1111 [17]
Wavelength- <span>distance between successive crests of a wave.

frequency- t</span><span>he rate at which something occurs or is repeated over time.

amplitude-</span><span> maximum extent of a vibration.</span>
6 0
3 years ago
You are given a parallel plate capacitor that has plates of area 27 cm^2 which are separated by 0.0100 mm of nylon (dielectric c
deff fn [24]

Answer:

Applied voltage should be 13.5396 kV

Explanation:

The charge stored by a capacitor when subjected to a potential difference 'v' across it's plates is given by

Q=\frac{K\epsilon _{o} A}{d}V

Solving for V we get

V=\frac{Qd}{K\epsilon _{o}A}

thus to store a charge of 0.11mC we solve for V as follows

Applying values we get

V=\frac{0.11\times 10^{-3}\times 0.01\times 10^{-3}}{27\times 10^{-4}\times 3.4\times 8.85\times 10^{-12}}

\therefore V=13.5396kV

7 0
3 years ago
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