Answer:
The mass of the cable is 4.94 kg
Explanation:
It is given that,
Mass of the block, m = 20 kg
Force applied to the cable, F = 110 N
Speed of the block, v = 4.2 m/s
Distance, d = 2 m
Let a is the acceleration of the block. It can be calculated using the third equation of motion as :
Let m' is the mass of the cable. It can be calculated using the second law of motion as :
m = 4.94 kg
So, the mass of the cable is 4.94 kg. Hence, this is the required solution.
The definition of average acceleration allows to find the result for the average acceleration in the given time interval is:
Instantaneous acceleration is defined as the derivative of velocity with respect to time.
a =
Where a is the acceleration, v the velocity and t the time.
They indicate that the speed of the car is given by the relation.
v = α t + β t²
With α = 3 m / s and β = 0.1 m / s³
Let's make the derivative.
a = α + 2β t
Let's substitute
a = 3 + 2 0.1 t
Average acceleration is the change in velocity in the time interval.
Let's find the velocity at the indicated time.
For t = 5 s
v₅ = 3 + 0.1 5²
v₅ = 5.5 m / s
For t = 10 s
v₁₀ = 3 + 0.1 10²
v₁₀ = 13 m / s
Let's calculate the average acceleration.
In conclusion using the definition of mean acceleration we can find the result for the mean acceleration in the given time interval is:
1.5 m / s²
Learn more here: brainly.com/question/20057878
Answer:
The work input during this process is -742 kJ
Explanation:
Given;
Initial temperature of nitrogen T₁ = 250 K
final temperature of nitrogen T₂ = 450 K
mass of nitrogen, m = 5 kg
The work input during the process is calculated as;
where;
R is gas constant = 0.2968 kJ/kgK
substitute given values in above equation.
Therefore, the work input during this process is -742 kJ