Tom puts a metallic cover over his car's windshield after parking. How does this control

What would be the final temperature of the system if all the heat lost by the copper block were absorbed by the water in the cal

ivanzaharov [21]

<span>Answer: q Cu = q H2O so, (121g)(0.385 J/g-K)(100.4C-x) = (150g)(4.18 J/g-K)(x-25.1C) x= 30.3C</span>

5 0

3 years ago

How to do number 19?

ivann1987 [24]

The answer is 8/3. You have to simplify each side and isolate the variable.

5 0

3 years ago

Read 2 more answers

A block, M1=10kg, slides down a smooth, curved incline of height 5m. It collides elastically with another block, M2=5kg, which i

erma4kov [3.2K]

Answer:

2.86 m

Explanation:

Given:

M₁ = 10 kg

M₂ = 5 kg

$\mu_k$ = 0.5

height, h = 5 m

distance traveled, s = 2 m

spring constant, k = 250 N/m

now,

the initial velocity of the first block as it approaches the second block

u₁ = √(2 × g × h)

or

u₁ = √(2 × 9.8 × 5)

or

u₁ = 9.89 m/s

let the velocity of second ball be v₂

now from the conservation of momentum, we have

M₁ × u₁ = M₂ × v₂

on substituting the values, we get

10 × 9.89 = 5 × v₂

or

v₂ = 19.79 m/s

now,

let the velocity of mass 2 when it reaches the spring be v₃

from the work energy theorem, we have

Work done by the friction force = change in kinetic energy of the mass 2

or

$0.5\times5\times9.8\times2 = \frac{1}{2}\times5\times( v_3^2-19.79^2)$

or

v₃ = 20.27 m/s

now, let the spring is compressed by the distance 'x'

therefore, from the conservation of energy

we have

Energy of the spring = Kinetic energy of the mass 2

or

$\frac{1}{2}kx^2=\frac{1}{2}mv_3^2$

on substituting the values, we get

$\frac{1}{2}\times250\times x^2=\frac{1}{2}\times5\times20.27^2$

or

x = 2.86 m

8 0

3 years ago

The x component of vector is 8.7 units, and its y component is -6.5 units. The magnitude of is closest to

irina1246 [14]

Answer:

F = 10.86 units

Explanation:

The magnitude of a vector in terms of the magnitude of its rectangular components is given by the following formula:

F = √(Fₓ² + Fy²)

where,

F = Magnitude of the Vector = ?

Fₓ = magnitude of the x-component of vector = 8.7 units

Fy = magnitude of y component of vector = - 6.5 units

Therefore, using these values in the equation, we get:

F = √[(8.7 units)² + (- 6.5 units)²]

F = √(117.94 units²)

<u>F = 10.86 units</u>

5 0

3 years ago

A cart starting from rest rolls down a frictionless 1.0 m high hill. It travels a distance 2.0 m along the rough bottom surface

Rzqust [24]

Answer:

Option B is correct.

Explanation:

Given data

Height of the hill = AB = 1 m

Distance traveled along the rough bottom surface = AC = 2 m

Now from the ΔABC

$\sin \theta = \frac{AB}{AC}$

$\sin \theta = \frac{1}{2}$

$\theta = 30$ °

We know that the coefficient of kinetic friction is

$\mu = \tan \theta$

$\mu = \tan 30$

$\mu =$ 0.5

This is the value of the coefficient of kinetic friction

Thus option B is correct.

8 0

3 years ago