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3 years ago

An object has a velocity of 8 m/s and a kinetic energy of 480 J what is the mass of the object

Physics

1 answer:

MaRussiya [10]3 years ago

7 0

We have first velocity equals 8 m/s and the kinetic energy is 480 J

The order is the mass of the object

We have this formula K= mv2/2 isolating the mass we have m=k/v2

Now we will have m=480/8×8 > m= 480/64 m= 7.5kg now we deternimed the mass it's 7.5 kg

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An infrared spectrometer on Dawn found something unexpected on Ceres's surface. Its presence suggested that Ceres might have for

Sati [7]

The question is missing alternatives. Here is the complete question.

An infrared spectrometer on Dawn found something unexpected on Ceres's surface. Its presence suggested that Ceres might have formed farther from the Sun, or been impacted by objects from a more-distant part of the solar system. What was this finding?

1. The fact that Ceres is covered with small dark particles that appear identical to the composition of Uranus's rings.

2. The presence of a thick cloud layer made of sulfuric acid, similar to what is observed at Venus.

3. The presence of clay-like minerals with ammonia bound up in them.

4. The infrared spectrum of Ceres's surface is essentially identical to that of most objects in the Kuiper Belt.

Answer: 3. The presence of clay-like minerals with ammonia bound up in them.

Explanation: The discovery of ammonia clay-like minerals in Ceres is surprising because it would be encoutered in planets that are far from the Sun, since ammonia requires colder temperatures, which is found beyond Jupiter's orbit, to condense. This finding can ascertain not only the origins of the dwarf planet as how the solar system was formed, were organized and evolved, because understanding where smaller planets are formed is important to determine their destiny.

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3 years ago

A step index fiber has a numerical aperture of NA = 0.1. The refractive index of its cladding is 1.465. What is the largest core

Vladimir [108]

Answer:

diameter = 9.951 × $10^{-6}$ m

Explanation:

given data

NA = 0.1

refractive index = 1.465

wavelength = 1.3 μm

to find out

What is the largest core diameter for which the fiber remains single-mode

solution

we know that for single mode v number is

V ≤ 2.405

and v = $\frac{2*\pi *r}{ wavelength} NA$

here r is radius

so we can say

$\frac{2*\pi *r}{ wavelength} NA$ = 2.405

put here value

$\frac{2*\pi *r}{1.3*10^{-6}} 0.1$ = 2.405

solve it we get r

r = 4.975979 × $x^{-6}$ m

so diameter is = 2 × 4.975979 × $10^{-6}$ m

diameter = 9.951 × $10^{-6}$ m

3 0

3 years ago

The amplitude of a wave is dependent upon what? A. the amount of energy carried by the wave B. the maximum displacement from the

storchak [24]

Given that amplitude and energy are related, the amplitude of a wave is dependent upon A. the amount of energy carried by the wave.
These two are connected, so one affects the other and vice versa.

7 0

2 years ago

Read 2 more answers

An object has moved through a distance. Can it have zero displacement? If yes, support your answer with an example.

aleksley [76]

Answer:

Yes, if object has moved through a distance, it surely can has zero displacement. as displacement is a vector quantity depending on starting and ending position not on the path.

For example, 1 circle of motion has distance 2πR but 0 displacement.

Explanation:

Yes, zero displacement is possible if an object has moved through a distance.

Suppose a ball starts moving from point A and it returns back at same point A, then the distance will be equal to 20 meters while displacement will be zero.

3 0

3 years ago

A 900 kg car initially going 15 m/s only in the x-direction runs into a stationary 1500 kg truck. After the collision the car is

Shalnov [3]

Answer:

6.97 m/s, 344 degree

Explanation:

mass of car, m = 900 kg, uc = 15 m/s, vc = 5 m/s, θ = 40 degree

mass of truck, M = 1500 kg, uT = 0, vT = ?, Φ = ?

Here, vT be the velocity of truck after collision and Φ its direction above x axis.

Use conservation of momentum in X axis

900 x 15 + 1500 x 0 = 900 x 5 Cos 40 + 1500 x vT Cos Φ

13500 - 3447.2 = 1500 vT CosΦ

vT CosΦ = 6.7 .....(1)

Use conservation of momentum in y axis

0 + 0 = 900 x 5 Sin 40 + 1500 vT SinΦ

vT SinΦ = - 1.928 .....(2)

Squarring both the equations and then add

vT^2 = 6.7^2 + (-1.928)^2

vT = 6.97 m/s

Dividing equation 2 by 1

tan Φ = - 1.928 / 6.7

Φ = - 16 degree

Angle from + X axis = 360 - 16 = 344 degree

6 0

3 years ago