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1 year ago

Which is the BEST example of the kind of mechanics that are studied in sports biometrics?

Physics

1 answer:

ikadub [295]1 year ago

5 0

Answer:

-A.

Explanation:

: Hope it's Help:

[correct me if I'm not correct]

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An LED with total power P tot = 960 mW emits UV light of wavelength 360 nm. Assuming the LED is 55% efficient and acts as an iso

Anit [1.1K]

Answer:

$E_0=225.09N/C$

Explanation:

We are given that

Power,Ptot=960mW= $960\times 10^{-3}W$

$1mW=10^{-3} W$

Wavelength, $\lambda=360 nm=360\times 10^{-9} m$

$1nm=10^{-9} m$

Distance,r=2.5 cm= $2.5\times 10^{-2} m$

1m=100 cm

Efficiency=55%

Power radiation emitted= $\frac{55}{100}\times 960\times 10^{-3}=0.528W$

Intensity,I= $\frac{P}{4\pi r^2}$

$I=\frac{0.528}{4\pi(2.5\times 10^{-2})^2}=67.26W/m^2$

Intensity, $I=\frac{1}{2}c\epsilon_0E^2_0$

$E^2_0=\frac{2I}{c\epsilon_0}$

Where $\epsilon_0=8.85\times 10^{-12}$

$c=3\times 10^8 m/s$

$E_0=\sqrt{\frac{2I}{c\epsilon_0}}$

$E_0=\sqrt{\frac{2\times 67.26}{3\times 10^8\times 8.85\times 10^{-12}}}$

$E_0=225.09N/C$

4 0

2 years ago

Convert 0.700 to scientific notation

ELEN [110]

Answer:

7 × 10^-1

Explanation:

Hope this helps :) mark branliest if you could!

7 0

2 years ago

An icy object moving through space in a highly eccentric orbit is called a

Daniel [21]

That's a good popular definition of a comet.

7 0

2 years ago

A point charge with a charge q1 = 2.30 μC is held stationary at the origin. A second point charge with a charge q2 = -5.00 μC mo

Alla [95]

Answer:

W = 2.74 J

Explanation:

The work done by the charge on the origin to the moving charge is equal to the difference in the potential energy of the charges.

This is the electrostatic equivalent of the work-energy theorem.

$W = \Delta U = U_2 - U_1$

where the potential energy is defined as follows

$U = \frac{1}{4\pi\epsilon_0}\frac{q_1q_2}{r^2}$

Let's first calculate the distance 'r' for both positions.

$r_1 = \sqrt{(x_1 - x_0)^2 + (y_1 - y_0)^2} = \sqrt{(0.170 - 0)^2 + (0 - 0)^2} = 0.170~m\\r_2 = \sqrt{(x_2 - x_0)^2 + (y_2 - y_0)^2} = \sqrt{(0.250 - 0)^2 + (0.250 - 0)^2} = 0.353~m$

Now, we can calculate the potential energies for both positions.

$U_1 = \frac{kq_1q_2}{r_1^2} = \frac{(8.99\times 10^9)(2.3\times 10^{-6})(-5\times 10^{-6})}{(0.170)^2} = -3.57~J\\U_2 = \frac{kq_1q_2}{r_2^2} = \frac{(8.99\times 10^9)(2.3\times 10^{-6})(-5\times 10^{-6})}{(0.3530)^2} = -0.829~J$

Finally, the total work done on the moving particle can be calculated.

$W = U_2 - U_1 = (-0.829) - (-3.57) = 2.74~J$

4 0

2 years ago

Read 2 more answers

Activities:

alisha [4.7K]

Answer: barometer.

A cyclone is a storm or system of winds that rotates around a center of low atmospheric pressure. An anticyclone is a system of winds that rotates around a center of high atmospheric pressure.

8 0

2 years ago