Hello there. <span> At ground level g is 9.8m/s^2. Suppose the earth started to increase its angular velocity. How long would a day be when people on the equator were just 'thrown off'? Why is the expression 'thrown off' a bad one ? </span> People would not be thrown off.
Let s = rate of rotation <span>Let r = radius of earth = 6,400km </span> <span>Then solving (s^2) r = g will give the desired rate, from which length of day is inferred. </span> <span>People would not be thrown off. They would simply move eastward in a straight line while the curved surface of earth fell away from beneath them.</span>
W = m.g = weight g = Gme/Re**2 where G= universal gravitational constant , Re= radius of the earth me= mass of the earth therefore it weighs 16 times less