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stealth61 [152]
3 years ago
11

At ground level g is 9.8m/s^2. Suppose the earth started to increase its angular velocity. How long would a day be when people o

n the equator were just 'thrown off'? Why is the expression 'thrown off' a bad one ?
Physics
2 answers:
Elina [12.6K]3 years ago
6 0
Hello there.
<span>
At ground level g is 9.8m/s^2. Suppose the earth started to increase its angular velocity. How long would a day be when people on the equator were just 'thrown off'? Why is the expression 'thrown off' a bad one ?
</span>
People would not be thrown off.

velikii [3]3 years ago
5 0
Let s = rate of rotation 
<span>Let r = radius of earth = 6,400km </span>
<span>Then solving (s^2) r = g will give the desired rate, from which length of day is inferred. </span>
<span>People would not be thrown off. They would simply move eastward in a straight line while the curved surface of earth fell away from beneath them.</span>
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<u>Projectile Motion</u>

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Being vo the initial speed of the object, θ the initial launch angle, and g=9.8m/s^2 the acceleration of gravity, then the maximum horizontal distance traveled by the object (also called Range) is:

\displaystyle d={\frac  {v_o^{2}\sin(2\theta )}{g}}

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\displaystyle d={\frac  {20^{2}\sin(2\cdot 30^\circ )}{9.8}}

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The range is 35.35 m

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