When it comes to optics, the most basic equation to use is the Snell's Law:
n₁ sin θ₁ = n₂ sin θ₂
where θ₁ is the angle of incidence, θ₂ is the angle of refraction, and n are the index of refractions depending on the type of medium.
This equation is used when light strikes from one medium to another and you want to determine the angle of refraction. For example, as light travels from air to water, the light bends as it strike the water. The observable change you can see is that things tend to look bigger when viewed from afar.
In this case, the first medium is air which has an index of refraction of 1. So, n₁ = 1. Then, n₂ is for the glass which is equal to 25°. Substituting the values,
(1) sin 25° = (1.5) sin θ₂
θ₂ = 16.36°
Two copper spheres are currently 1.2 meters apart. One sphere has a charge of +2.2•10-4 C and the other has a charge of -8.9•10-4 C, then the the force between the charged spheres is the force attractive.
<h3>What is Coulomb's law?</h3>
Coulomb's law can be expressed as that the electrical force between two charged bodies is directly proportional to the product of the quantity of charge on the bodies and inversely proportional to the square of the separation distance between the two bodies.
As given in the problem two copper spheres are currently 1.2 meters apart.One sphere has a charge of +2.2•10-4 C and the other has a charge of - 8.9•10-4 C.
As per coulomb's law, opposite charges attract each other.
Thus, If one sphere has a charge of +2.2•10-4 C and the other has a charge of -8.9•10-4 C, then the the force between the charged spheres is the force attractive.
Learn more about Coulomb's law here ;
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Answer:
Forces 1 and 2 cannot have equal magnitudes.
Force 1 exceeds force 2.
Explanation:
Numbering the given statements:
- The force of the horse pulling on the cart.
- The force of the cart pulling on the horse.
- The force of the horse pushing on the road
.
- The force of the road pushing on the horse.
- When a horse pulls a cart along a flat road starting from the state of rest, the horse applies a force on the ground in downward-back direction diagonally and as its reaction it moves forward. During this action there is also a reaction force by the road on the horse which exceeds the force of the horse on the ground and as a result the horse moves forward.
- For pulling the cart the horse applies the force on the cart in the forward direction and as a reaction the cart applies a force on the horse in the backward direction which is less than the force of the horse on the cart resulting in the forward motion of the cart along with the horse.