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geniusboy [140]
3 years ago
11

When a -COOH group replaces a hydrogen in a hydrocarbon the result is a/an

Chemistry
1 answer:
soldier1979 [14.2K]3 years ago
4 0

Answer:

drugs

Explanation:

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Organelles are
bixtya [17]

Answer:

o responsible for digestion in the cell

o found outside of the membrane

3 0
2 years ago
How many moles of ammonia are in 1.20 x10 25 molecules of ammonia?
aleksley [76]
The  moles    of  ammonia  in  1.20  x10^25  molecules  of  ammonia  is  calculated  as  follows

by  use   of   Avogadro    constant

1moles =  6.02  x10^23

what  about    1.20  x10^25  moles

by  use  of  cross  multiplication

=   1 mole   x  (  1.20  x10^25)  /(   6.02  x10^23)   =  19.93  moles   
7 0
3 years ago
A chemical reaction in which bonds are broken is usually associated with ________. a chemical reaction in which bonds are broken
Reika [66]

Answer:The answer to the question is the release of energy. The bonds that bind a molecules atom's act as a storage of energy. One way it is released is when those bonds are broken and it is released outward in every direction. This breakage results in smaller molecules and not the formation of a larger molecule.

Explanation:

7 0
2 years ago
2 KClO_2 produces 2 KCl+ 3O_2 when heated. If this reaction produces 82.8 g of KCl how many grams of O2 were produced?
Ad libitum [116K]

Answer:

37.046 grams of oxygen gas were produced.

Explanation:

2KClO_2\rightarrow 2KCl+ 3O_2

Moles of potassium chlorite = \frac{82.2 g}{106.5 g/mol}=0.7718 mol

According to reaction 2 moles of potassium chlorite gives 3 moles of oxygen gas.

Then 0.7718 moles of potassium chlorite will give:

\frac{3}{2}\times 0.7718 mol=1.1577 mol of oxygen gas.

Mass of 1.1577 moles of oxygen gas:

1.1577 mol × 32 g/mol = 37.046 g

37.046 grams of oxygen gas were produced.

4 0
3 years ago
A saturated solution of lead(ii) fluoride, pbf2, was prepared by dissolving solid pbf2 in water. the concentration of pb2+ ion i
katrin [286]

Equation :

PbF2 ------> Pb2+ + 2F-

Solubility product is given as:

Ksp = [Pb2+][F-]^2

let x = [Pb2+]

Ksp = x(2x)^2 = 4(x)^3 = 4(2.08*10^-3)^3

Ksp = 3.60*10^-8

8 0
3 years ago
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