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Mashcka [7]
3 years ago
10

What kind of bond is formed between a metal and a nonmetal? Explain your answer.

Chemistry
2 answers:
anzhelika [568]3 years ago
8 0

Answer:

Ionic Bonds

Explanation:

Ionic Bonds - A bond between metal and nonmetal elements. Involves transferring electrons. Covalent Bonds - Also known as molecular bonds. A bond between two nonmetals.

Hope this helps

shusha [124]3 years ago
5 0

Answer:

NVIDIA GeForce RTX 3080 10GB GDDR6X PCI Express 4.0 Graphics Card

Explanation:

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A typical adult human body contains approximately 2.500 L of blood plasma. How many grams of blood plasma are in the typical adu
kirill115 [55]

Answer:

m=2.575g

Explanation:

Hello,

In this case, since the density is defined as the ratio of the mass and volume:

\rho =\frac{m}{V}

We can compute the mass of blood as follows:

m=\rho *V=1.03g/L*2.500L\\\\m=2.575g

Best regards.

7 0
3 years ago
What is the mass of a substance in 0.5 mol of nh3​
KATRIN_1 [288]

Answer:

17 g/mol

Explanation:

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6 0
3 years ago
Bombardment of cobalt-59 with a neutron produces a manganese-56 atom and another particle. What is this particle?A. an alpha par
Aleksandr-060686 [28]

Answer:A

Explanation:

A nuclear reaction is balanced by ensuring that the Masses and charges of te reactants and products are exactly balanced on the left and right hand side of the reaction equation. If there are 60 mass units on the LHS and manganese has only 56 mass units then four mass units are left. If there is no charge on a neutron and there is a charge of 27 on the cobalt, then two charges are left. Four mass units and a charge of +2 corresponds to a helium which is actually an alpha particle.

4 0
3 years ago
Calculate the amount of heat gained when one 250 gram bottle is heated from 25oC to 30oC. The specific heat of water is 4.18 J/g
Fed [463]

Answer:

5230J

Explanation:

Mass (m) = 250g

Initial temperature (T1) = 25°C

Final temperature (T2) = 30°C

Specific heat capacity (c) = 4.184J/g°C

Heat energy (Q) = ?

Heat energy (Q) = Mc∇T

Q = heat energy

M = mass of the substance

C = specific heat capacity

∇T = change in temperature = T2 - T1

Q = 250 × 4.184 × (30 - 25)

Q = 1046 ×5

Q = 5230J

The heat energy required to raise the temperature of 250g of water from 25°C to 30°C is 5230J

7 0
3 years ago
Read 2 more answers
A sample of water (88 grams) had a temperature change of 6.0 ℃. What was the heat change of this sample? (q = m c ΔT, c = 4.18 J
jeka94

Answer:

Q=2209J

Explanation:

Hello!

In this case, since the heat involved during a heating process is computed in terms of mass, specific heat and temperature change as shown below:

Q=mC\Delta T

Thus, since the heated mass of water was 88 g, the specific heat of water is 4.184 J/g°C and the temperature change is 6.0 °C, we can compute the heat as shown below:

Q=88g*4.184\frac{J}{g\°C}*6.0\°C \\\\Q=2209J

Best regards!

7 0
3 years ago
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