Question

What is the balanced equation for the combustion of 1-naphthol, c10h7oh, to give co2 and h2o? do not include phases.

Answer 1

Answer:

$C_1_0H_7OH (l) + 23/2 O_2 (g) \longrightarrow 10 CO_2 (g) + 4 H_2O (g)$  

Explanation:

Hi, the reaction you asked for is the complete combustion of 1-naphthol in which the naphthol reacts with oxygen producing water and carbon dioxide:

$C_1_0H_7OH (l) + O_2 (g) \longrightarrow CO_2 (g) + H_2O (g)$

Steps to balance:

1) Number of $CO_2$ equal to the C in the naphthol:

$C_1_0H_7OH (l) + O_2 (g) \longrightarrow 10 CO_2 (g) + H_2O (g)$

2) Number of $H_2O$  equal to half the H in the naphthol:

$C_1_0H_7OH (l) + O_2 (g) \longrightarrow 10 CO_2 (g) + 4 H_2O (g)$

2) Balance the $O_2$ equal to O in $CO_2$ and $H_2O$ minus the O in the naphthol :

$C_1_0H_7OH (l) + 23/2 O_2 (g) \longrightarrow 10 CO_2 (g) + 4 H_2O (g)$  

If you prefer, write the equation in non-fractional numbers:

$2 C_1_0H_7OH (l) + 23 O_2 (g) \longrightarrow 20 CO_2 (g) + 8 H_2O (g)$  

Answer 2

:  2 C10H7OH + 23 O2 → 20 CO2 + 8 H2O 
hope it helps