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2 years ago

There are_____________ centimeters in 1 meter.

Physics

2 answers:

Setler [38]2 years ago

8 0

There is 100 centimeters in a meter

ivanzaharov [21]2 years ago

6 0

Answer: 100

Explanation:

just multiply the value by 100 :)

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How much work is done to move 2.10 μC of charge from the negative terminal to the positive terminal of a 3.50 V battery?

rjkz [21]

Answer:

6.3E-6

Explanation:

Workdone = V Q

4 0

3 years ago

To calibrate the calorimeter electrically, a constant voltage of 3.6 V is applied and a current of 2.6 A flows for a period of 3

hodyreva [135]

Answer : The correct option is, (c) $3.7\times 10^2J/^oC$

Explanation :

First we have to calculate the energy or heat.

Formula used :

$E=V\times I\times t$

where,

E = energy (in joules)

V = voltage (in volt)

I = current (in ampere)

t = time (in seconds)

Now put all the given values in the above formula, we get:

$E=(3.6V)\times (2.6A)\times (350s)$

$E=3276J$

Now we have to calculate the heat capacity of the calorimeter.

Formula used :

$C=\frac{E}{\Delta T}=\frac{E}{T_{final}-T_{initial}}$

where,

C = heat capacity of the calorimeter

$T_{initial}$ = initial temperature = $20.3^oC$

$T_{final}$ = final temperature = $29.1^oC$

Now put all the given values in this formula, we get:

$C=\frac{3276J}{(29.1-20.3)^oC}$

$C=372.27J/^oC=3.7\times 10^2J/^oC$

Therefore, the heat capacity of the calorimeter is, $3.7\times 10^2J/^oC$

7 0

3 years ago

If the angle of reflection is 25 degrees, the angle of incidence is

natali 33 [55]

Answer:

25 degrees

Explanation:

The angle of incidence equals the angle of reflection

7 0

3 years ago

In a pickup game of dorm shuffleboard,students crazed by final exams use a broom to propel a calculus book along the dorm hallwa

Yakvenalex [24]

Answer:

Coefficient of friction between the book and floor is 0.582.

Explanation:

Using the velocity formula;

v^2 = 2as

a = v^2/(2s)

a = 1.6^2/(2*0.9)

a = 2.56/1.8

a = 1.42 m/s^2

the force necessary to give the book the acceleration is

F = ma = 3.5*1.42 (m is mass of the book i.e. 3.5 kg)

F = 4.98 N

The difference in the force is the friction force, which is

Ff = 25 - 4.98 = 20 N

Ff = mgμ

where μ is coefficient of friction and g is acceleration due to gravity that is 9.8 m/s^2

μ = Ff/mg

μ = 20/(3.5*9.81)

μ = 0.582

Coefficient of friction between the book and floor is 0.582.

6 0

2 years ago

A 73-kg boy is surfing and catches a wave which gives him an initial speed of 1.6 m/s. He then drops through a height of 1.60 m,

Gnesinka [82]

To solve this problem it is necessary to apply the concepts related to the Conservation of Energy, for which it is necessary that any decrease made through the potential energy, is equivalent to the gain given in the kinetic energy or vice versa.

Mathematically this can be expressed as

$KE_i+PE_i = KE_f+PE_f$

Since there is no final potential energy (the height is zero), and the initial potential energy is equivalent to the work done we have to

$W = KE_f-KE_i-PE_i$

$W = \frac{1}{2}mv_f^2-\frac{1}{2}mv_i^2 -mgh$

$W =\frac{1}{2} m(v_f^2-v_i^2)-mgh$

$W= \frac{1}{2}(73)(8.5^2-1.6^2)-(73*9.8*1.6)$

$W= 1399.045J$

$W= 1.4kJ$

Therefore the non-conservative work was done on the boy is 1.4kJ

4 0

3 years ago