All categories

3 years ago

There are_____________ centimeters in 1 meter.

Physics

2 answers:

Setler [38]3 years ago

8 0

There is 100 centimeters in a meter

ivanzaharov [21]3 years ago

6 0

Answer: 100

Explanation:

just multiply the value by 100 :)

You might be interested in

A Michelson interferometer uses red light with a wavelength of 656.45 nm from a hydrogen discharge lamp. Part A How many bright-

kati45 [8]

Answer:

51793 bright-dark-bright fringe shifts are observed when the mirror M2 moves through 1.7cm

Explanation:

The number of maxima appearing when the mirror M moves through distance \Delta L is given as follows,

$\Delta m = \frac{\Delta L}{\frac{\lambda}{2}}$

Here,

$\Delta L$ = is the distance moved by the mirror M

$\lambda$ is the wavelenght of the light used.

$\Delta L$ = 0.017m

$\lambda = 656.45*10^{-9}m$

$\Delta m = \frac{0.017}{\frac{656.45*10^{-9}}{2}}$

$\Delta m = 51793.72$

Therefore, 51793 bright-dark-bright fringe shifts are observed when the mirror M2 moves through 1.7

3 0

3 years ago

A(n) 1400-kg car going at 6.32 m/s in the positive x direction collides with a 2900-kg truck at rest. The collision is totally i

tresset_1 [31]

Answer:

a) Acceleration of the car is given as

$a_{car} = -21 m/s^2$

b) Acceleration of the truck is given as

$a_{truck} = 10.15 m/s^2$

Explanation:

As we know that there is no external force in the direction of motion of truck and car

So here we can say that the momentum of the system before and after collision must be conserved

So here we will have

$m_1v_1 + m_2v_2 = (m_1 + m_2)v$

now we have

$1400 (6.32) + 2900(0) = (1400 + 2900) v$

$v = 2.06 m/s$

a) For acceleration of car we know that it is rate of change in velocity of car

so we have

$a_{car} = \frac{v_f - v_i}{t}$

$a_{car} = \frac{2.06 - 6.32}{0.203}$

$a_{car} = -21 m/s^2$

b) For acceleration of truck we will find the rate of change in velocity of the truck

so we have

$a_{truck} = \frac{v_f - v_i}{t}$

$a_{truck} = \frac{2.06 - 0}{0.203}$

$a_{truck} = 10.15 m/s^2$

5 0

3 years ago

What is the function of the labeled structures? A: B: C:

poizon [28]

Answer:

A: receives information

B: Carries information away from the cell body

C: Delivers information to the next cell

Explanation:

4 0

3 years ago

Read 2 more answers

N the reactants of the general form of the single replacement reaction, the 'B' represents a _________ cation.

IrinaVladis [17]

1. Metallic

2. A, B

3. Unreactive

these are all right.

7 0

3 years ago

Read 2 more answers

Compare the light gathering power of a 1 meter diameter telescope to that of the human eye ,which has a diameter of roughly 2.5

lesantik [10]

Answer:

The telescope can gather light 1600 times more than the human eyes can!

Explanation:

The light gathering ability of an optical element is directly proportional to its area of opening.

So, in comparing the light gathering abilities for two objects, it is just the ratio of their area of opening.

Let the diameter of the telescope be D = 1 m

And the diameter of the human eyes be d = 2.5 cm = 0.025 m

Light gathering ability of the telescope compared to the eyes = D² ÷ d²

= (D²/d²) = (1²/0.025²) = 1600 times.

The telescope can gather light 1600 times more than the human eyes can!

Hope this Helps!!!

7 0

3 years ago