Explanation:
1)
A) Bb BB
B) 50%
2)
A) 50%
B) <u> </u><u> </u><u> </u><u> </u><u> </u><u>b</u><u>.</u><u> </u><u> </u><u> </u><u>b</u>
B. Bb. Bb
b. bb. bb
When someone stands against a locker and is does not moving at all, then there will be no displacement and since displacement = 0
Work done also becomes equal to zero.
Work done is usually defined as change in energy. Since the work done is zero there has been no energy used.
Answer:
2100 J
Explanation:
Parameters given:
Force acting on the object, F = 420 N
Distance moved by object, d = 5m
The change in kinetic energy of an object is equal to the work done by a force acting on the object:
W = F * d
∆KE = F * d
∆KE = 420 * 5
∆KE = 2100 J
Explanation:
Given
radius


mass disc 
mass of person 
velocity of Person 
moment of inertia 

Initial angular momentum



Final Moment inertia


final angular momentum

Conserving angular momentum



So based on your question where there is a block of mass m1= 8.8kg in the inclined plane with an angle of 41 with respect to the horizontal. To find the spring constant of the problem were their is a coefficients of friction of 0.39 and 0.429, you must use the formula K*x^2=m*a*sin(angle). By calculating the minimum spring constant is 220.66 N/m^2