Answer:
divide the distance by the time and get average velocity in units of s. the detection to the left
As per the question the distance of venus from sun is given as 0.723 AU
We have been asked to calculate the time period of the planet venus.
As per kepler's laws of planetary motion the square of time period of planet is directly proportional to the cube of semi major axis. mathematically

⇒
where is k is the proportionality constant
We may solve this problem by comparing with the time period of the earth . We know that time period of earth is 365.5 days
Hence
The distance of sun from earth is taken as 1 AU i.e the mean distance of earth from sun
Hence 
The distance of venus from sun is 0.723 AU i.e
From keplers law we know that-
⇒
Putting the values mentioned above we get-

⇒
⇒
Hence the time period of venus is 224.388352752710 days
Answer:
<u><em>The plank moves 0.2m from it's original position</em></u>
Explanation:
we can do this question from the constraints that ,
- the wheel and the axle have the same angular speed or velocity
- the speed of the plank is equal to the speed of the axle at the topmost point .
thus ,
<em>since the wheel is pure rolling or not slipping,</em>
<em>⇒
</em>
where
<em>
- speed of the wheel</em>
<em>
- angular speed of the wheel</em>
<em>
- radius of the wheel</em>
<em>since the wheel traverses 1 m let's say in time '
' ,</em>
<em>
</em>
∴
⇒
the speed at the topmost point of the axle is :
⇒
this is the speed of the plank too.
thus the distance covered by plank in time '
' is ,
⇒
<em>Time = (the set distance) / (the object's traveling speed)</em>