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3 years ago

13

What equation would you use to find the time taken for an object to travel a set distance?

1 answer:

3241004551 [841]3 years ago

6 0

<em>Time = (the set distance) / (the object's traveling speed)</em>

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A beam of light bends when it passes from air into water, and then bends even more when it passes from water into glass. What ca

Nikolay [14]

Answer:

Certain Things Make Light Bend?

Explanation:

Transparent Objects/ things can make light bend when entering through it.

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2 years ago

A solar cooker, really a concave mirror pointed at the sun, focuses the sun's rays 16.0 cm in front of the mirror. what is the r

VARVARA [1.3K]

The focal point of a concave mirror is halfway along the radius, therefore the radius would be 2•16= 32 cm

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2 years ago

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A. two forces

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3 years ago

A 0.106-A current is charging a capacitor that has square plates 4.60 cm on each side. The plate separation is 4.00 mm.

nikdorinn [45]

Answer:

a

$\frac{d \phi_{E}}{dt} =1.1977 *10^{10} \ V\cdot m/s$

b

$I = 0.106 \ A$

Explanation:

From the question we are told that

The current is $I = 0.106 \ A$

The length of one side of the square $a = 4.60 \ cm = 0.046 \ m$

The separation between the plate is $d = 4.0 mm = 0.004 \ m$

Generally electric flux is mathematically represented as

$\phi_E = \frac{Q}{\epsilon_o}$

differentiating both sides with respect to t is

$\frac{d \phi_{E}}{dt} = \frac{1}{\epsilon_o} * \frac{d Q}{ dt}$

=> $\frac{d \phi_{E}}{dt} = \frac{1}{\epsilon_o} *I$

Here $\epsilon_o$ is the permitivity of free space with value

$\epsilon _o = 8.85*10^{-12} C/(V \cdot m)$

=> $\frac{d \phi_{E}}{dt} = \frac{0.106}{8.85*10^{-12}}$

=> $\frac{d \phi_{E}}{dt} =1.1977 *10^{10} \ V\cdot m/s$

Generally the displacement current between the plates in A

$I = 8.85*10^{-12} * 1.1977 *10^{10}$

=> $I = 0.106 \ A$

3 0

2 years ago

A car travels in a flat circle of radius R. At a certain instant the velocity of the car is 24 m/s west and the total accelerati

lisov135 [29]

Answer with Explanation:

We are given that

Velocity,v=24 m/s west

Acceleration,a= $2.5m/s^2$

$\theta=53^{\circ}$ (N of W)

Horizontal component of acceleration=Tangential acceleration

Tangential acceleration, $a_x=acos\theta=2.5cos53=1.505 m/s^2$

Radial acceleration=Vertical acceleration= $a_y=asin\theta$

$a_y=2.5sin53=1.998 m/s^2$

Radial acceleration, $a_y=\frac{v^2}{R}$

$1.998=\frac{(24)^2}{R}$

$R=\frac{(24)^2}{1.998}$

$R=288.29 m$

Time, $t=\frac{2\pi R}{velocity}$

$t=\frac{2\pi(288.29)}{24}$

$t=75.47 s$

8 0

2 years ago