3 years ago

What equation would you use to find the time taken for an object to travel a set distance?

Physics

1 answer:

3241004551 [841]3 years ago

6 0

<em>Time = (the set distance) / (the object's traveling speed)</em>

You might be interested in

Se um corpo 1 está em movimento em relação a um corpo 2, e se o corpo 2 está em repouso em relação a um corpo 3, pode-se afirmar

stealth61 [152]

Yo habla ingles no espanol

8 0

3 years ago

Read 2 more answers

A bug crawls 3.0 mm east, 4.0mm north, and then 5.0 mm at 45 north of east. Draw a diagram showing its displacements and determi

KatRina [158]

Answer:

Explanation is given

Mark Me as Branliest

3 0

3 years ago

A boat floats in water a. Archimedes b. Bernoulli c. Density d. Pascal e. Pressure

Ivenika [448]

The answer is Density !, Do you also need an example ?

Rate this the brainliest answer , Thank youuu !

7 0

3 years ago

Read 2 more answers

On earth, two parts of a space probe weigh 14500 N and 4800 N. These parts are separated by a center-to-center distance of 18 m

Nastasia [14]

Answer:

$F = 1.489*10^{-7} N$

Explanation: Weight of space probes on earth is given by: $W= m*g$

W= weight of the object( in N)

m= mass of the object (in kg)

g=acceleration due to gravity(9.81 $\frac{m}{s^{2} }$ )

Therefore,

$m_{1} = \frac{14500}{9.81}$

$m_{1} = 1478.08 kg$

Similarly,

$m_{2} = \frac{4800}{9.81}$

$m_{2} = 489.29 kg$

Now, considering these two parts as uniform spherical objects

Also, according to Superposition principle, gravitational net force experienced by an object is sum of all individual forces on the object.

Force between these two objects is given by:

$F = \frac{Gm_{1} m_{2}}{R^{2} }$

G= gravitational constant ( $6.67 * 10^{-11} m^{3} kg^{-1} s^{-2}$ )

$m_{1} , m_{2}$ = masses of the object

R= distance between their centres (in m)(18 m)

Substituiting all these values into the above formula

$F = 1.489*10^{-7} N$

This is the magnitude of force experienced by each part in the direction towards the other part, i.e the gravitational force is attractive in nature.

7 0

3 years ago

True or false, the older rocks tend to be closer to the tear in the ocean floor

Natali5045456 [20]

Answer:

false!!

your welcome!!!!

4 0

2 years ago