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Otrada [13]
4 years ago
11

An oxygen cylinder used in a hospital contains 35.4 L of oxygen gas at a pressure of 149.6 atm. How much volume would the oxygen

occupy if it were transferred to a container that maintained a pressure of 1.00 atm if the temperature remains constant
Chemistry
1 answer:
Aliun [14]4 years ago
6 0

Answer: 5296 L

Explanation:

To calculate the new volume, we use the equation given by Boyle's law. This law states that pressure is directly proportional to the volume of the gas at constant temperature.

The equation given by this law is:

P_1V_1=P_2V_2

where,

P_1\text{ and }V_1 are initial pressure and volume.

P_2\text{ and }V_2 are final pressure and volume.

We are given:

P_1=149.6atm\\V_1=35.4L\\P_2=1.00atm\\V_2=?

Putting values in above equation, we get:

149.6\times 35.4L=1.00\times V_2\\\\V_2=5296L

Thus volume occupied by oxygen if it were transferred to a container that maintained a pressure of 1.00 atm if the temperature remains constant is 5296 L

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The metal zirconium becomes superconducting at temperatures below 3.4000K.
dybincka [34]

Answer:

-269.75 degrees Celsius

Explanation:

7 0
3 years ago
Balancing equations
Bad White [126]
Make sure you numbers with variable are on one side and the numbers 

7 0
4 years ago
HELLPPPPP MEEEEEE
umka2103 [35]

The products and the reactants are the components of the reaction. The equation of phosphoric acid represents the decomposition reaction as it forms oxygen and water. Thus, option a is correct.

<h3>What is a decomposition reaction?</h3>

A decomposition reaction is a  chemical breakdown of the reactant into two or more products. The large and complex compound breaks into smaller and simpler molecules.

The following equation, 4 H₃PO₄ → P₄ + 5 O₂ + 6 H₂O is an example of decomposition as phosphoric acid breaks into phosphorus, water, and oxygen molecules.

Therefore, option a. the reaction of phosphoric acid is a decomposition reaction.

Learn more about decomposition reaction here:

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3 0
2 years ago
Lead has a density of 11.3 g/cm3 . what is the volume of a 15.1 g block of lead?
natita [175]
Hey there:

density = 11.3 g/cm³

mass = 15,1 g

Therefore: 

D = m / V

11.3 = 15.1 / V

V = 15.1 / 11.3

V = 1.336 cm³
3 0
3 years ago
g Suppose you are titrating vinegar, which is an acetic acid solution of unknown concentration, with a sodium hydroxide solution
Elza [17]

Answer: The molar concentration of acetic acid in the vinegar is 0.539 M.

Explanation:

The formula used is:

M_1V_1=M_2V_2

where,

M_1 and V_1 are the concentration and volume of base.

M_2 and V_2 are the concentration and volume of an acid.

Given:

Molar concentration of NaOH = 0.1798 M

Volume of NaOH = 30.01 mL

Volume of acetic acid = 10.0 mL

Now putting all the given values in the above formula, we get:

M_1V_1=M_2V_2\\\\0.1798M\times 30.01mL=M_2\times 10.0mL\\\\M_2=0.539M

Thu, the molar concentration of acetic acid in the vinegar is 0.539 M.

4 0
3 years ago
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