Question

Zn+2HCl=ZnCl2+H2 How many grams of ZnCl2 will be produced from 26.0 g of Zn and 42.0 g of HCl?

Answer 1

53.14 grams of Zn$Cl_{2}$  will be produced from 26.0 g of Zn and 42.0 g of HCl.

Explanation:

Balanced chemical reaction:

Zn + 2 HCl ⇒ Zn$Cl_{2}$ +  $H_{2}$

data given:

mass of Zn = 26 grams

mass of HCl = 42 grams

mass of Zn$Cl_{2}$ = ?

here in the reaction Zn is the limiting reagent so mass of

Zn$Cl_{2}$ formed will be determined by it.

atomic mass of zinc =65.38 grams/mole

number of moles = $\frac{mass}{atomic mass of 1 mole}$

putting the values in the above equation:

number of moles of zinc = $\frac{26}{65.38}$

number of moles of zinc = 0.39 moles

From the balanced reaction it is seen that

1 mole of Zn produced 1 mole of Zn$Cl_{2}$

0.39 moles will produce x moles of Zn$Cl_{2}$

0.39 moles of Zn$Cl_{2}$ (atomic mass of  Zn = 65.38 grams/mole)

mass = atomic mass x number of moles

         = 0.39 x 136.28

           = 53.14 grams

53.14 grams of Zn$Cl_{2}$ is formed