Question

What is the average atomic mass of the following isotopic mixture - 42.10 g/mole- 93.50%; 48.30 g/mole 6.200%; 50.40 g/mole - 0.3000%? Show your work!!

Answer 1

Answer:

40.03g/mole

Explanation:

Given parameters:

Mass =  42.10 g/mole and abundance  = 93.50%

Mass = 8.30 g/mole and abundance =  6.200%

Mass  = 50.40 g/mole and abundace  = 0.3000%

Find;

Average atomic mass = ?

Solution:

Average atomic mass = sum (mass x abundance)

 Average atomic mass = ($\frac{93.50}{100} x 42.1$) + ($\frac{6.2}{100}$ x 8.3) + ($\frac{0.3}{100} x 50.4$)

                                      = 39.36g/mole + 0.52g/mole + 0.15g/mole

                                      = 40.03g/mole