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Komok [63]
3 years ago
9

Determine the correct name for the compound, C3H8. In organic chemistry, this is referred to as propane. A) Tricarbon hexahydrid

e B) Tricarbon octahydride C) Tetracarbon octahydride D) Tetracarbon hexahydride
Physics
2 answers:
Leya [2.2K]3 years ago
8 0
Well, since it's C3, we need Tricarbon, and H8 means Octa-, so B is your answer: Tricarbon Octahydride.

Hope this helps~!
mestny [16]3 years ago
8 0

Answer:

The correct name for the compound C_{3}H_{8} is tricarbon octahydride.

(C) is correct option.

Explanation:

The given compound  C_{3}H_{8} is a covalent compound. the compounds in which there is a sharing of electrons between  two elements is called covalent compound. here, there is sharing of electrons between hydrogen and carbon.

Hydrogen and carbon are non metal and hence will form covalent bond.

Property of the name of covalent bond is given by,

(I). First we have to write the name more electronegative element and then less electronegative element.

(II). The atoms of an element is greater than 1, then we add to prefixes which are  as follows,

For 1 atom = mono

For 2 atom = di

For 3 atom = tri

For 4 atom = tatra

For 5 atom = penta

For 6 atom = hexa

For 7 atom = septa

For 8 atom = octa and so on.

So, The name of the compound will be tricarbon octahydride

Hence, The correct name for the compound C_{3}H_{8} is tricarbon octahydride.  

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An aircraft flying at a steady velocity of 70 m/s eastwards at a height of 800 m drops a package of supplies.
iren2701 [21]

The motion of the package can be described as the motion of a projectile,

given that it has an horizontal velocity and it is acted on by gravity.

  • a) \vec{v} = 70·i
  • b) The package will reach ground in approximately <u>12.77 seconds</u>.
  • c) The speed of the package as it lands is approximately <u>145.51 m/s</u>.
  • d) The path of the package based on a stationary frame of reference is <u>parabolic</u>
  • e) The path of the package as seen from the plane is <u>directly vertical</u> downwards

Reasons:

Velocity of the aircraft = 70 m/s

Direction of flight of the aircraft = Eastward

Height from which the aircraft drops the package, h = 800 m

a) The initial velocity of the package, \vec{v} = 70·i

b) The time it will take the package to reach the ground, <em>t</em>, is given by the formula;

\displaystyle h = \mathbf{\frac{1}{2} \cdot g \cdot t^2}

Where;

g = The acceleration due to gravity ≈ 9.81 m/s²

Therefore;

\displaystyle t = \mathbf{\sqrt{ \frac{2 \cdot h}{g} }}

Which gives;

\displaystyle t = \sqrt{ \frac{2 \times 800}{9.81} } \approx \mathbf{12.77}

The time it will take the package to reach the ground, t ≈ <u>12.77 seconds</u>

c) The vertical velocity just before the package reaches the ground, v_y, is given as follows;

v_y^2 = 2·g·h

Therefore;

v_y = √(2·g·h)

Which gives;

v_y = √(2 × 9.81 × 800) ≈ 125.28

v_y ≈ 125.28 m/s

Which gives; \vec{v} = 70·i - 125.28·j

Therefore, |v| = √(70² + (-125.28)²) ≈ 143.51

The speed of the package as it lands, |v| ≈ <u>143.51 m/s</u>

d) The motion of the package that includes both horizontal and vertical motion is a projectile motion.

Therefore;

The path of the package is the path of a projectile, which is a <u>parabolic shape</u>.

e) As seen by someone on the aeroplane, the horizontal velocity will be

zero, therefore, the package will appear as accelerating <u>directly vertical</u>

downwards.

Learn more about projectile motion here:

brainly.com/question/1130127

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Answer:

When the mass is drawn upwards and let go, the force of gravity accelerates it,

Explanation:

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