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Schach [20]
2 years ago
5

“I am sure I will get a good grade on this project. I’ve worked really hard; my teacher will recognize my efforts!” This stateme

nt reflects ___________.
a.
femininity
b.
individualism
c.
decentralization
d.
collectivism
Physics
2 answers:
kvasek [131]2 years ago
6 0

B. individualism is the correct answer

Pachacha [2.7K]2 years ago
4 0
The answer would be b., individualism. Femininity is obviously out the picture and decentralization means "The transfer of authority from central to local government. and collectivism is "<span>the practice or principle of giving a group priority over each individual in it." And since the statement says "...my teacher will recognize MY efforts!" and not OUR efforts, then it isn't collectivism.</span>
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Which element contains a full 2p orbital in its valence shell
alex41 [277]
So Neon ( Ne) is the correct answer.

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3 years ago
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An oil gusher shoots crude oil 25.0 m into the air through a pipe with a 0.100-m diameter. Neglecting air resistance but not the
Mariana [72]

Answer:3764.282 KPa

Explanation:

Given gusher shoots oil at h=25 m

i.e. the velocity of jet is

v=\sqrt{2gh}[/tex]

v=22.147 m/s

Now the pressure loss in pipe is given by hagen poiseuille equation

\Delta P=\frac{32L\mu v}{D^2}

\Delta P=\frac{32\times 50\times 22.147\times 1}{10^{-2}}

\Delta P=3543.557 KPa

For  25 m head in terms of Pressure

\Delta P_2=\rho \times g\times h=220.725 KPa

Total Pressure=\Delta P+\Delta P_2=3543.557+220.725=3764.282 KPa

4 0
3 years ago
The coefficient of kinetic friction between an object and the surface upon which it is sliding is 0.10. The mass of the object i
denis-greek [22]

Answer:

Explanation:

1) Force Friction = Normal Force * Coefficient of Friction

Force Friction = Mass * Gravity * Coefficient of Friction

2) F = ma

Force = mass * acceleration

Force Friction (from #1) = mass * acceleration

acceleration = Force Friction / Mass

6 0
2 years ago
A 3 kg toy car with a speed of 7 m/s collides head-on with a 2 kg car traveling in the opposite direction with a speed of 5 m/s.
Mademuasel [1]

Answers:

kinetic energy lost = 86.4J

Explanation:

let Kf be the kinetic energy after the collision and Ki be the kinetic energy before the collision. let the 3kg car be 1 and 2kg car be 2.

Kf = K1(f) + K2(f)

Ki = K1(i) + k2(i)

loss in kinetic energy = Kf - Ki

                                 = 1/2(3)(2.20)^2 + 1/2(2)(2.20)^2 - 1/2(3)(7)^2 - 1/2(2)(-5)^2

                                 = 12.1 - 98.5

                                 = -86.4 J

therefore, the kinetic energy lost in the collision is 86.4 J.

6 0
2 years ago
A 2.10 cm × 2.10 cm square loop of wire with resistance 1.30×10−2 Ω has one edge parallel to a long straight wire. The near edge
Troyanec [42]

Answer:

I_{l} =44.84 \mu A

Explanation:

given,

side of square loop = a = 2.10 cm

Resistance of the wire =  1.30×10⁻² Ω  

Length of the loop = c = 1.10 cm

rate of increasing current = 130 A/s

\phi = \dfrac{\mu_0Ib}{2\pi}(ln(\dfrac{c+a}{c}))

\dfrac{d\phi}{dt}= \dfrac{\mu_0b}{2\pi}\dfrac{dI}{dt}(ln(\dfrac{c+a}{c}))

I_{l} = \dfrac{V}{R}

I_{l} = \dfrac{1}{R}\dfrac{d\phi}{dt}

I_{l} = \dfrac{1}{R}\dfrac{\mu_0b}{2\pi}\dfrac{dI}{dt}(ln(\dfrac{c+a}{c}))

I_{l} = \dfrac{1}{1.3 \times 10^{-2}}\dfrac{4\pi\times 10^{-7}\times 0.021}{2\pi}\times 130\times (ln(\dfrac{0.011+0.021}{0.011}))

I_{l} =44.84 \times 10^{-6}\A

I_{l} =44.84 \mu A

3 0
3 years ago
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