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Allushta [10]
3 years ago
14

If the speed of an object is increasing, then the forces acting on that object must be ________.

Physics
1 answer:
In-s [12.5K]3 years ago
5 0

Answer:

Unbalanced.

Explanation:

Usually, unbalanced forces cause acceleration, or increased movement.

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A tiny sphere carrying a charge of 6. 5 µc sits in an electric field, at a point where the electric potential is 240 v. what is
vodka [1.7K]

The sphere’s Electric potential energy is 1.6*10^{-6}J

Given,

q=6. 5 µc, V=240 v,

We know that sphere’s Electric potential energy(E) = qV=6.5*10^{-6} *240=1.6*10^{-6}J

<h3>Electric potential energy</h3>

The configuration of a certain set of point charges within a given system is connected with the potential energy (measured in joules) known as electric potential energy, which is a product of conservative Coulomb forces. Two crucial factors—its inherent electric charge and its position in relation to other electrically charged objects—can determine whether an object has electric potential energy.

In systems with time-varying electric fields, the potential energy is referred to as "electric potential energy," but in systems with time-invariant electric fields, the potential energy is referred to as "electrostatic potential energy."

A tiny sphere carrying a charge of 6. 5 µc sits in an electric field, at a point where the electric potential is 240 v. what is the sphere’s potential energy?

Learn more about Electric potential energy here:

brainly.com/question/24284560

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8 0
1 year ago
PLS PLS PLS PLS PLS PLS PLS PLS PLS PLS PLS HELP
7nadin3 [17]

Answer:

The poles of an electromagnet can even be reversed by reversing the flow of electricity. If a wire carrying an electric current is formed into a series of loops, the magnetic field can be concentrated within the loops. ... All of their little magnetic fields add together, creating a stronger magnetic field.

Explanation:

8 0
3 years ago
What is the name of the units that are normally used to measure energy?
Sati [7]

The basic unit of energy is a joule. Kill calories measure the energy available in food.

8 0
3 years ago
Object A has mass 83.0 g and hangs from an insulated thread. When object B, which has a charge of +140 nC, is held nearby, A is
erastova [34]

Answer:

a) -238 nC  

b) 0.889 N  

Explanation:

Concepts and Principles

<u>Particle in Equilibrium:</u> If a particle maintains a constant velocity (so that a = 0), which could include a velocity of zero, the forces on the particle balance and Newton's second law reduces to:  

∑F = 0                                                                           (1)  

<u>Coulomb's Law:</u> the magnitude of the electrostatic force exerted by a point charge q1 on a second point charge q2 separated by a distance r is directly proportional to the product of the two charges and is inversely proportional to the square of the distance between them:

F_12 = k*| q1 |*| q2 |/r^2                                                 (2)

where k = 8.99 x 10^9 N  m^2/C^2 is Coulomb constant.  

<u>Given Data  </u>

<em>mA (mass object A) = (83 g)*(1/1000g)=0.09 kg </em>

<em>qB (charge of object B) = (140 nC)*(1/10^9 nC) = 130 x 10^-9 C </em>

<em>Object A is attracted to object B. </em>

<em>Ф(angle made by object A with the vertical) = 7.2°  </em>

<em>(  r (distance between the two objects) = (5 cm) * (1 m/ 100 cm) =0.05 m  </em>

<em>Object A is in equilibrium.  </em>

Required Data

In part (a), we are asked to determine the charge qA of object A.

In part (b), we are asked to determine the tension T in the thread.  

(a) The FBD in Figure 1 shows the forms acting on object A; Fe is the electric force exerted on object A by object B, T is the tension force exerted on the thread, and m_a*g is the gravitational force exerted on object A.  

Model object A as a particle in equilibrium in the horizontal and vertical direction and apply Equation (1) to it:  

∑F_x = F_e-Tsin = 0                                   F_e=Tsin<em>Ф                </em><em>(3)</em>

∑F_y = Tcos<em>Ф - </em>m_a*g= 0                      m_a*g=Tsin<em>Ф                </em><em>(4)</em>

Divide Equation (3) by Equation (4) to eliminate T:

F_e/m_a*g=tan<em>Ф</em>

F_e=m_a*g*tan<em>Ф</em>

Substitute for  F_e by using Coulomb's law from Equation (2):

k*| q_A |*| q_B |/r = m_a*g*tan<em>Ф</em>

Solve for q_A :  

| q_A | = m_a*g*tanФ_r/k*| q_B |

Substitute numerical values from given data:

| q_A | =  238 nC  

Because object A is attracted to object B. it has an opposite negative charge. Therefore, the charge on object A is | q_A | =  -238 nC  

(b)  

Solve Equation (4) for T:  

T = m_a*g/cosФ

Substitute numerical values from given data:

T = (0.09 kg)(9.8 m/s^2) /cos 7.2°  

  = 0.889 N  

4 0
3 years ago
if a car engine does 600,000 J of work over a 500m distance and the mass of the car is 250Kg then what is the final velocity of
drek231 [11]

Given that

Work = 600,000 J ,

distance(S) = 500 m ,

mass (m) = 250 Kg ,

Determine the velocity of car (v) = ?

                 We know that,

                                Work = Force × distance

                               => Force = Work ÷ distance

                                              = 600,000 ÷ 500

                                              = 500 N .

                   Also Force F =  m.a  ; from Newtons II law

                                      500 = 250 × a  

                                             a = 2 m/s.

<em>Final Velocity from the given  formula </em>

                                     V² = u² + 2.a.s

                                         = 0 + 2 × 2 × 500

                                         = \sqrt{2000}

                                    <em>   v = 44.7 m/s</em>

8 0
3 years ago
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