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3 years ago

6x+6= x squared + x How do I deal with the x squared when solving for x

Mathematics

2 answers:

lukranit [14]3 years ago

8 0

I honestly think it has two solutions
X=-1
X=6

Klio2033 [76]3 years ago

8 0

I need 20 characters lol

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What type of number is -2i?

Iteru [2.4K]

Answer:

It is an imaginary number.

Step-by-step explanation:

In this example, the real number is -2 is being multiplied by the imaginary unit, i, which i can be also expressed as (√-1).

7 0

3 years ago

Find the number to sides of a regular polygon if the sum of the interior angles are 7560

Stels [109]

Use S=(n-2)180
S is the sum and N is the number of sides
If you know that the sum is 7560 then plug that in for S
7560=(n-2)180
Then solve for n
7560=180n-360 (note I used distributive property)
7560+360=180n
7920=180n
7920/180=n
n=44 sides
I hope this helps :)

6 0

4 years ago

Given k(x)=4x+5, if k(x)=-3 find x

zvonat [6]

Answer:

x=-5/7

Step-by-step explanation:

4 0

3 years ago

Radioactive Waste The rate at which radioactive waste is entering the atmosphere at time t is decreasing and is given by Pe^-kt,

Dmitry_Shevchenko [17]

Answer:

$\displaystyle{\int^{\infty}_0 {50e^{-0.04t}}\, dt}=1250$

Step-by-step explanation:

Given:

$T =\displaystyle{\int^{\infty}_0 {Pe^{-kt}} \, dt}$

where,

T = total amount of waste

P = 50, the initial rate

k = 0.04

t = time

$T =\displaystyle{\int^{\infty}_0 {50e^{-0.04t}} \, dt}$

now we need to solve this integral!

$T =\displaystyle{50\int^{\infty}_0 {e^{-0.04t}} \, dt}$

$T = \left|50\left(\dfrac{e^{-0.04t}}{-0.04}\right)\right|^{\infty}_0$

$T = \left|-1250e^{-0.04t}\right|^{\infty}_0$

$T = (-1250e^{-0.04(\infty)})-(-1250e^{-0.04(0)})$

when any number has a power of negative infinity it is 0. because: $a^-{\infty} = \dfrac{1}{a^{\infty}} = \dfrac{1}{\infty} = 0$ , like something being divided by a very large number!

$T = (-1250(0))-(-1250e^0)$

$T = 1250$

this is the total amount of waste

6 0

3 years ago

Work out the length of AB.

4vir4ik [10]

$\frac{AB}{BC}$ =    $\frac{EB}{DC}$

$\frac{AB}{BC}$ =    $\frac{1.75 m}{7 m}$

let AB = E

⇒     (AB) (7 m) = (1.75 m) ( BC + AB)
  (AB) (7 m) = (1.75 m) (1.5 m + AB)
    = 2.625 m² + (1.75 m ) (AB)
(AB) (7 m - 1.75 m) = 2.625 m²
  ∴ AB = 2.625 m²  ÷ (5.25 m)

<span> ⇒ the length of AB is 0.5 m</span>

7 0

3 years ago