What’s the Answer.............

__________ death rates and __________ infant mortality rates are due in large part to technological advances, improved sanitatio

Elis [28]

<h2>Both are Lower</h2>

Explanation:

Death rate is also known as Mortality rate.

Death rate is the ratio of total deaths to total population in a specific area or community over a specific time period.
Death rate = number of deaths/1000 of the population/year.
The death of young children under the age of 1 is known as Infant mortality rate.

The infant mortality rate (IMR) meausres the death toll which is the number of deaths of children under one year of age /1000 live births.

4 0

3 years ago

What is uv rays??????

Crazy boy [7]

Answer:

<em>Ultraviolet is a form of electromagnetic radiation with wavelength from 10 nm to 400 nm, shorter than that of visible light, but longer than X-rays. UV radiation is present in sunlight, and constitutes about 10% of the total electromagnetic radiation output from the Sun. </em>

3 0

2 years ago

Read 2 more answers

Human activity in recent years has drastically altered biomes. Because of this, conservation and preservation of biomes should b

castortr0y [4]

I think TRUE
Humans alteration of the global environment has triggered the sixth major extinction event in the history of life and caused widespread changes in the global distribution of organisms.

3 0

4 years ago

24)

dsp73

File is attached for the Answer

3 0

3 years ago

Hexokinase can use glucose or fructose as a substrate. The Km forglucose is 0.15 mM and for fructose Km = 1.5 mM.

babymother [125]

Answer:

a) glucose because Km is less for glucose.

b) For glucose, V as a percentage of Vmax = 50 %

For fructose, V as a percentage of Vmax = 9 %

Explanation:

a) Hexokinase has highest affinity for glucose because it's Km for glucose is low.

When enzyme [E] binds a substrate [S] an [ES] complex is formed. It is represent as under:

[E] + [S] ⇌ [ES] ⇌ [E] + [P]

As soon as [ES] is formed it may either form [E] & [P] in a forward reaction or dissociate back into [E] & [S]. Km is known as dissociation constant which represents the extent to which [E] & [S] are being formed. A higher value of Km represents formation of more [E] & [S] back from [ES]. It also means that binding affinity of enzyme with substrate is less or we can say that Km is inversely proportional to binding affinity.

Km ∝ 1 / binding affinity.

So, it simply means that lower the Km more will be the affinity of the enzyme for the substrate. In the given question, Km for glucose is 0.15 mM which is less than fructose (Km for fructose = 1.5 mM) that is why glucose is the answer.

b) The formula for Michaelis–Menten equation is as under:

V = Vmax × [S] / ([S] + Km)

V / Vmax = [S] / ([S] + Km)

Here, for glucose Km = 0.15 mM and [S] = 0.15mM.

So V as a percentage of Vmax for glucose will be as under:

V / Vmax = 0.15/0.15 + 0.15

→ V / Vmax = 0.15/0.30

→ V / Vmax = 0.5 = 1/2 = 50 %

Here, for fructose Km = 1.5 mM and [S] = 0.15mM.

So V as a percentage of Vmax for fructose will be as under:

V / Vmax = 0.15/0.15 + 1.5

→ V / Vmax = 0.15/1.65

→ V / Vmax = 0.09 = 9/100 = 9 %

5 0

3 years ago