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3 years ago

4 1/2 newtons is approximately equal to 1 what

Chemistry

1 answer:

Anettt [7]3 years ago

6 0

4 1/2 newtons is approximately equal to 1 pound,

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What willl happen if we nuke the sun some how

iogann1982 [59]

Answer:

The sun'll likely absorb the radiation if it is close enough (Which it will never be)

Explanation:

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3 years ago

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Identify the precipitate(s) formed when solutions of na2so4(aq), ba(no3)2(aq), and nh4clo4(aq) are mixed.

Lostsunrise [7]

Answer : BaS $O_{4}$ will be the precipitate which will be formed.

Explanation : When all the three solutions namely; $NaSO_{4} + Ba(NO_{3})_{2} + NH_{4} ClO_{4}$ are mixed together a white precipitate of BaS $O_{4}$ is formed as a product in the solution along with the soluble by product of Ammonium nitrate which is $NH_{4} NO_{3}$

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3 years ago

How many nucleons are there in an atom with a nuclear charge of +20 and 23 neutrons?

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Explanation:

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3 years ago

Please help ASAP

aev [14]

Answer:

1st one is correct, Igneous rocks are formed when molten rock cools and hardens.

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3 years ago

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A laser pulse with wavelength 525 nm contains 4.40 mj of energy. How many photons are in the laser pulse

Alexandra [31]

The laser pulse in this question has a wavelength of $\lambda=524 nm=525\times 10^{-9}m$ . To solve this problem, we first have to calculate the energy of a single photon in the laser pulse. The equation for calculating the energy of a single photon of an electromagnetic wave is $E=\frac{hc}{\lambda}$ where $c$ is the speed of light, $h$ is planks constant and $\lambda$ is the wave length of the photons.

For this problem, $c=3.0\times 10^8m/s$ , $h=6.63\times10^{-34}J.s$ and $\lambda=525\times 10^{-9}m$ . We use these values to calculate the energy of the photon as shown below,

$E=\frac{hc}{\lambda} \\E=\frac{(6.63\times 10^{32}Js)\times(3.0\times10^8m/s)}{525\times 10^{-9}m} \\E=3.79\times 10 ^{-19}J.$

Now that we know the energy for a single photon, we will divide the total energy given by the energy of one photon to get the number of photons in the pulse. The number of photons $n$ is calculated as shown below,

$n=\frac{4.4\times 10^{-3}J}{3.79\times10^{-19}J} =1.16\times 10^{16}$ . There are $1.16\times 10^{16}$ photons.

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3 years ago