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Komok [63]
3 years ago
14

What willl happen if we nuke the sun some how

Chemistry
2 answers:
malfutka [58]3 years ago
8 0
The nuke would burn up and turn into dust on its course to the sun, it would not be able to make impact in the sun before this has happened
iogann1982 [59]3 years ago
4 0

Answer:

The sun'll likely absorb the radiation if it is close enough (Which it will never be)

Explanation:

You might be interested in
What is the energy of a microwave photon that has a frequency of 9.86 x 1012 Hz?
BlackZzzverrR [31]

Answer:

6.533 × 10^-21J

Explanation:

The energy of the microwave photon can be calculated using:

E = hf

Where;

E = energy of photon (J)

h = Planck's constant (6.626 × 10^-34 J/s)

f = frequency (9.86 x 10^12 Hz)

Hence, E = hf

E = 6.626 × 10^-34 × 9.86 x 10^12

E = 65.33 × 10^(-34 + 12)

E = 65.33 × 10^(-22)

E = 6.533 × 10^-21J

The energy of the microwave photon is

6.533 × 10^-21J

5 0
3 years ago
Which statement best summarizes what happens during cellular respiration?
morpeh [17]

Answer:

A

Explanation:

B and D have to do with plants

and C has nothing to do with cellular resporation.

8 0
2 years ago
Read 2 more answers
Purchasing the correctly sized BMX bike is based on the height of the rider. In order to fit a customer, the salesman can use th
Phantasy [73]
Answer: Your best answer is A.

Explanation: 1.35 is a constant and thus is does not change. The equation can be simplified to-
“b = (0.29 x h)+ 1.35”
So, if your rider is say 60 inches tall, the equation would change to-
“b = (0.29 x 60)+ 1.35”
Then to-
“b = (17.4) + 1.35” or “b = 17.4 + 1.35”
And therefore the size of the BMX bike frame in inches would be-
“b = 18.75”

Hope this helped :)
5 0
2 years ago
In a 0.730 M solution, a weak acid is 12.5% dissociated. Calculate Ka of the acid.
Mamont248 [21]

Answer:

Approximately 1.30 \times 10^{-2}, assuming that this acid is monoprotic.

Explanation:

Assume that this acid is monoprotic. Let \rm HA denote this acid.

\rm HA \rightleftharpoons H^{+} + A^{-}.

Initial concentration of \rm HA without any dissociation:

[{\rm HA}] = 0.730\; \rm mol \cdot L^{-1}.

After 12.5\% of that was dissociated, the concentration of both \rm H^{+} and \rm A^{-} (conjugate base of this acid) would become:

12.5\% \times 0.730\; \rm mol \cdot L^{-1} = 0.09125\; \rm mol \cdot L^{-1}.

Concentration of \rm HA in the solution after dissociation:

(1 - 12.5\%) \times 0.730\; \rm mol \cdot L^{-1} = 0.63875\; \rm mol\cdot L^{-1}.

Let [{\rm HA}], [{\rm H}^{+}], and [{\rm A}^{-}] denote the concentration (in \rm mol \cdot L^{-1} or \rm M) of the corresponding species at equilibrium. Calculate the acid dissociation constant K_{\rm a} for \rm HA, under the assumption that this acid is monoprotic:

\begin{aligned}K_{\rm a} &= \frac{[{\rm H}^{+}] \cdot [{\rm A}^{-}]}{[{\rm HA}]} \\ &= \frac{(0.09125\; \rm mol \cdot L^{-1}) \times (0.09125\; \rm mol \cdot L^{-1})}{0.63875\; \rm mol \cdot L^{-1}}\\[0.5em]&\approx 1.30 \times 10^{-2} \end{aligned}.

5 0
3 years ago
Need help asap<br> will give brainly
uranmaximum [27]

Answer:

8. B

9. D

10. A

Explanation:

give brainliest pls ^-^

4 0
2 years ago
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