Reactants- Water, Light, Carbon dioxide
Products- Oxygen and Glucose
<h3>
Answer:</h3>
0.342 mol Ca
<h3>
General Formulas and Concepts:</h3>
<u>Math</u>
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Chemistry</u>
<u>Atomic Structure</u>
<u>Stoichiometry</u>
- Using Dimensional Analysis
<h3>
Explanation:</h3>
<u>Step 1: Define</u>
13.7 g Ca
<u>Step 2: Identify Conversions</u>
Molar Mass of Ca - 40.08 g/mol
<u>Step 3: Convert</u>
- Set up:

- Multiply/Divide:

<u>Step 4: Check</u>
<em>Follow sig fig rules and round. We are given 3 sig figs.</em>
0.341816 mol Ca ≈ 0.342 mol Ca
A (they are experimentally determined exponents)
Answer:
The rate of the catalyzed reaction will increase by a 1.8 × 10⁵ factor.
Explanation:
The rate of a reaction (r) is proportional to the rate constant (k). We can find the rate constant using the Arrhenius equation.

where,
A: collision factor
Ea: activation energy
R: ideal gas constant
T: absolute temperature (125°C + 273 = 398 K)
For the uncatalized reaction,

For the catalized reaction,

The ratio kC to kU is 6.0 × 10⁻⁸A/3.4 × 10⁻¹³A = 1.8 × 10⁵