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Komok [63]
3 years ago
14

What willl happen if we nuke the sun some how

Chemistry
2 answers:
malfutka [58]3 years ago
8 0
The nuke would burn up and turn into dust on its course to the sun, it would not be able to make impact in the sun before this has happened
iogann1982 [59]3 years ago
4 0

Answer:

The sun'll likely absorb the radiation if it is close enough (Which it will never be)

Explanation:

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What are the reactants and products of photosynthesis.
andrey2020 [161]
Reactants- Water, Light, Carbon dioxide
Products- Oxygen and Glucose
7 0
3 years ago
How many moles are in a 13.7g block of calcium?
goldenfox [79]
<h3>Answer:</h3>

0.342 mol Ca

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Reading a Periodic Table

<u>Stoichiometry</u>

  • Using Dimensional Analysis
<h3>Explanation:</h3>

<u>Step 1: Define</u>

13.7 g Ca

<u>Step 2: Identify Conversions</u>

Molar Mass of Ca - 40.08 g/mol

<u>Step 3: Convert</u>

  1. Set up:                               \displaystyle 13.7 \ g \ Ca(\frac{1 \ mol \ Ca}{40.08 \ g \ Ca})
  2. Multiply/Divide:                 \displaystyle 0.341816 \ mol \ Ca

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

0.341816 mol Ca ≈ 0.342 mol Ca

6 0
3 years ago
What are mand n in the rate law equation?<br> Rate = k[A]”[B]"
frez [133]

A (they are experimentally determined exponents)

6 0
3 years ago
The activation energy of an uncatalyzed reaction is 95 kJ / mol. The addition of a catalyst lowers the activation energy to 55 k
dybincka [34]

Answer:

The rate of the catalyzed reaction will increase by a 1.8 × 10⁵ factor.

Explanation:

The rate of a reaction (r) is proportional to the rate constant (k). We can find the rate constant using the Arrhenius equation.

k=A.e^{-Ea/R.T}

where,

A: collision factor

Ea: activation energy

R: ideal gas constant

T: absolute temperature (125°C + 273 = 398 K)

For the uncatalized reaction,

kU=A.e^{-95\times 10^{3} kJ/mol /(8.314J/K.mol).398K}=3.4\times 10^{-13}A

For the catalized reaction,

kC=A.e^{-55\times 10^{3} kJ/mol /(8.314J/K.mol).398K}=6.0\times 10^{-8}A

The ratio kC to kU is 6.0 × 10⁻⁸A/3.4 × 10⁻¹³A = 1.8 × 10⁵

8 0
4 years ago
Which of the following has the greatest mass, in grams?1) 1 atom of gold (Au) 2) 1.0 mol mercury (Hg) atoms 3) 2.0 mole of chlor
vlada-n [284]

c is the answer for ur question

3 0
3 years ago
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