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Andre45 [30]
3 years ago
13

Identify the precipitate(s) formed when solutions of na2so4(aq), ba(no3)2(aq), and nh4clo4(aq) are mixed.

Chemistry
1 answer:
Lostsunrise [7]3 years ago
7 0

Answer : BaSO_{4} will be the precipitate which will be formed.


Explanation : When all the three solutions namely; NaSO_{4}  + Ba(NO_{3})_{2}  + NH_{4} ClO_{4} are mixed together a white precipitate of BaSO_{4} is formed as a product in the solution along with the soluble by product of Ammonium nitrate which is NH_{4} NO_{3} 

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Which element, if combined with chlorine, will have the greatest attraction for the chlorine electrons? N P As
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Which of the following is not an organic compound?<br> OC6H14<br> O CO₂<br> OCH4<br> C12H22011
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How many particles are present in 10.0 moles of table salt?
Dima020 [189]

1.01 x 10^24 molecules.

Explanation:

To calculate the number of molecules in a given number of mole, we can simply multiply by Avogadro's number which is equal to 6.022 x 10 ^23.

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I hope this helps :)

7 0
2 years ago
What is the mass of 1.7 × 1023 atoms of zinc (Zn)?
Rudiy27

Number of moles is defined as the ratio of given mass in g to the molar mass.

The mathematical formula is:

Number of moles = \frac{given mass in g}{molar mass}   (1)

Number of zinc atoms is equal to 1.7\times10^{23}, by Avogadro number, number of moles can be calculated.

As, 1 mol=6.022\times10^{23} atoms, hence,

1.7\times10^{23}\times\frac{1 mol}{6.022\times10^{23} }

= 0.2822 mol

Now, from formula (1), calculate mass in g (molar mass of zinc = 65.4 g/mol)

0.2822 mol = \frac{mass in g}{65.4 g/mol}

mass in g  = {0.2822 mol \times 65.4 g/mol

= 18.45588 g

Thus, by rounding off the above number, it will come near about 19 g approximately.

Hence, option (C) is the correct answer.



 



8 0
3 years ago
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