Answer:
In-F bond has the largest dipole moment.
Explanation:
Given the electronegativities:
Ge= 2.01
O= 3.44
H= 2.20
P= 2.19
In= 1.78
F= 3.98
B= 2.04
N= 3.04
The bond between Ge and O has an electronegativity difference:
ED= 3.44 - 2.01= 1.43
The bond between H and P has an electronegativity difference:
ED= 2.20 - 2.19= 0.01
The bond between In and F has an electronegativity difference:
ED= 3.98 - 1.78= 2.20
The bond between B and N has an electronegativity difference:
ED= 3.04 - 2.04= 1.00
As In-F bond has the largest electronegativity difference, this is the covalent bond with the largest dipole moment.
The structural formula for 2-methylpentane is in Figure 1. It shows all the C-C and C-H bonds explicitly.
The bond-line formula for 2-methylpentane is in Figure 2. We assume that a carbon atom is at the ends and junctions of the lines. We do not show the H atom, but we mentally assume that there are enough to give each carbon a valence of four.
A condensed structural formula is designed to be typed <em>all on one line</em>. We could write the condensed structural formula for 2-methylpentane as either (CH₃)₂CH-CH₂-CH₂-CH₃ or CH₃CH(CH₃)CH₂CH₂CH₃.
The horizontal C-C bonds are <em>optional </em>— you can include or omit them as desired.
The smallest particle of a covalently bonded compound is an atom.
The correct answer is C, too deep in the Earth to collect. Hope this helps!
Answer:
Explanation:
- For the balanced reaction:
<em>4Fe(s) + 3O₂(g) → 2Fe₂O₃(s).</em>
It is clear that 4 mol of Fe react with 3 mol of O₂ to produce 2 mol of Fe₂O₃.
- Firstly, we need to calculate the no. of moles of 35.8 grams of Fe metal:
no. of moles of Fe = mass/molar mass = (35.8 g)/(55.845 g/mol) = 0.64 mol.
- Now, we can find the no. of moles of O₂ is needed to react with the proposed amount of Fe:
<em><u>Using cross multiplication:</u></em>
4 mol of Fe is needed to react with → 3 mol of O₂, from stichiometry.
0.64 mol of Fe is needed to react with → ??? mol of O₂.
∴ The no. of moles of O₂ needed = (3 mol)(0.64 mol)/(4 mol) = 0.48 mol.
- Finally, we can get the volume of oxygen using the information:
<em>It is known that 1 mole of any gas occupies 22.4 L at standard P and T (STP).</em>
<em></em>
<em><u>Using cross multiplication:</u></em>
1 mol of O₂ occupies → 22.4 L, at STP conditions.
0.48 mol of O₂ occupies → ??? L.
∴ The no. of liters of O₂ = (0.48 mol)(22.4 L)/(1 mol) = 10.752 L.
