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Pavel [41]
3 years ago
7

Astronomers determine that a certain square region in interstellar space has an area of approximately 2.4 \times 10^72.4×10 ​7 ​

​ (light-years)2, where a light-year is a unit of astronomical distance. Assuming that this region is a square, then a single side of the square would be approximately how many light-years long?
Physics
1 answer:
mafiozo [28]3 years ago
5 0

Answer:

1.5 × 10³⁶ light-years

Explanation:

A certain square region in interstellar space has an area of approximately 2.4 × 10⁷² ​​ (light-years)². The area of a square can be calculated using the following expression.

A = l²

where,

A is the area of the square

l is the side of the square

l = √A = √2.4 × 10⁷² ​​ (light-years)² = 1.5 × 10³⁶ light-years

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Answer:

Option c

Explanation:

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A compass in a magnetic field will will comply with the magnet's North pole directing towards the magnetic field.

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At what point on the hill will the car have zero gravitational potential energy?
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At the bottom of the hill
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2. Two toy cars are involved in a race. Car A has mass m while car B has mass 2m. a. The two cars have the same force applied to
ArbitrLikvidat [17]

Answer:

a) The kinetic energy of the two cars is the same

the moment of car 2 is greater than the moment of car 1

b)  the kinetic energy of car 1 is greater than that of car 2

the moment of the two cars is the same

Explanation:

a) to know the kinetic energy of each car, we must find the speed, use Newton's second law to find the acceleration

Car 1

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Let's use kinematics to find the velocity after x = 1 m

       v² = v₀² + 2 a x

The initial speed is zero

       v = √ (2 F/m  x)

For the distance of x = 1 m

        v₁ = √ (2 F / m)

Car 2

      F = 2m a

      a = F / 2m

      v² = 2 a x

      v = √ (F/m  x)

 For x = 1 m

       v₂ = √(F / m)

Let's calculate the kinetic energy of each car

Car 1

      K₁ = ½ m v₁²

      K₁ = ½ m 2F / m

      K₁ = F

Car 2

      K₂ = ½ 2m v₂²

      K₂ = ½ 2m F / m

      K₂ = F

The kinetic energy of the two cars is the same

Let's calculate the moment

Car 1

   P₁ = m v₁

   P₁ = m √ (2F / m)

Car 2

    P₂ = 2m v²

    P₂ = 2m √(F / m)

We see that the moment of car 2 is greater than the moment of car 1

b) in this part the force is applied by t = 10 s

Acceleration is the same, let's find the speed

Car1

          v = v₀ + a t

          v = F / m t

          v₁ = F / m 10

Car 2

           v₂ = F / 2m 10

           v₂ = F / m 5

Let's calculate the kinetic energy of each car

Car 1

           K₁ = ½ m v₁²

           K₁ = ½ m (F / m 10)²

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Car2

         K₂ = ½ 2m v₂²

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In this case we see that the kinetic energy of car 1 is greater than that of car 2

Let's calculate the moment

Car 1

         P₁ = m v₁

         P₁ = m F / m 10

         P₁ = 10 F

 

Car 2

        P₂ = 2m v₂

        P₂ = 2m F / m 5

        P₂ = 10 F

In this case the moment of the two cars is the same

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can you have all of them as possibilities ???

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