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maksim [4K]
3 years ago
8

Which of the following is a characteristic property of noble gases? A. They only react with each other B. They do not react chem

ically C. They react violently in water D. They react violently in air.
Chemistry
1 answer:
tresset_1 [31]3 years ago
8 0

Answer:

B.They do not react chemically

Explanation:

This is because all noble gases haves full outer shell therefore they don’t participate in bonding.They are referred to as inert which means unreactive.

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saul85 [17]
It has the slowest rotation of all planets. 

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Which option explains how purple pigments make some flower petals purple?
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Many of the actual chemicals in flower petals that give them their different colors are called anthocyanins. These are water-soluble compounds that belong to a bigger class of chemicals known as flavonoids. Anthocyanins are responsible for creating the colors blue, red, pink, and purple in flowers.

3 0
3 years ago
A certain first-order reaction is 27.5 percent complete in 8.90 min at 25°C. What is its rate constant?
jeyben [28]

Answer:

k= 0.145min^{-1}

Explanation:

Hello there!

In this case, according to the given information, it turns out necessary for us remember that the first-order kinetics is given by:

ln(A/A_0)=-kt

Whereas the 27.5% complete means A/Ao=0.275, and thus, we solve for the rate constant as follows:

k=\frac{ln(A/A_0)}{-t}

Then, we plug in the variables to obtain:

k=\frac{ln(0.275)}{-8.90min}\\\\k= 0.145min^{-1}

Regards!

4 0
3 years ago
Classify the following mixturesin their proper column​
PolarNik [594]

Answer:

homogeneous mixtures: iron,alcohol,zonrox,wine.

heterogeneous mixtures: smoke,batchoy,spaghetti,halo halo,book,clothes.

8 0
3 years ago
How many atoms of oxygen are present in 7.51 grams of<br> glycine with formula C₂H5O2N?
Blizzard [7]

1.205 × 10²³ atoms of oxygen will be present in 7.51 grams of glycine with formula C₂H5O2N. Details about number of atoms can be found below.

How to calculate number of atoms?

The number of atoms of a substance can be calculated by multiplying the number of moles of the substance by Avogadro's number.

However, the number of moles of oxygen in glycine can be calculated using the following expression:

Molar mass of C₂H5O2N = 75.07g/mol

Mass of oxygen in glycine = 32g/mol

Hence; 32/75.07 × 7.51 = 3.2grams of oxygen in glycine

Moles of oxygen = 3.2g ÷ 16g/mol = 0.2moles

Number of atoms of oxygen = 0.2 × 6.02 × 10²³ = 1.205 × 10²³ atoms

Therefore, 1.205 × 10²³ atoms of oxygen will be present in 7.51 grams of glycine with formula C₂H5O2N.

Learn more about number of atoms at: brainly.com/question/8834373

#SPJ1

3 0
2 years ago
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