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maksim [4K]
3 years ago
8

Which of the following is a characteristic property of noble gases? A. They only react with each other B. They do not react chem

ically C. They react violently in water D. They react violently in air.
Chemistry
1 answer:
tresset_1 [31]3 years ago
8 0

Answer:

B.They do not react chemically

Explanation:

This is because all noble gases haves full outer shell therefore they don’t participate in bonding.They are referred to as inert which means unreactive.

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A ________ is an electric circuit that produces a magnetic field
aksik [14]
I believe it would be D. Electromagnet. It's been a while since I've done this stuff, tho. Hope this helps!!!! :)
5 0
3 years ago
How many moles of glucose (C6H12O6) are in 5.0 liters of a 2.5 M C6H12O6 solution?
zhannawk [14.2K]
N = M x V      

n = 2.5 x 5.0
 
n = 12.5 moles of C6H12O6
5 0
3 years ago
What is the pH range for an acid? <br> 0-7<br> 7-14<br> 7<br> 0
olga nikolaevna [1]
<h3>Answer: Choice A)  0-7</h3>

Explanation:

If the pH is between 0 and 7, then we have an acid.

If the pH is between 7 and 14, then we have an alkaline base.

If pH = 7, then it's neutral.

7 0
3 years ago
Read 2 more answers
One mole of an ideal gas with a volume of 1.0 L and a pressure of 5.0 atm is allowed to expand isothermally into an evacuated bu
Deffense [45]

Answer:

w= - 1.7173 kJ, q= 1.7173 kJ, q(rev) = 1717.3 J = 1.7173 kJ.

Explanation:

Okay, from the question we are given the information below;

Number of moles, n= 1 mole; initial volume, v(1) = 1.0 litres (L); pressure (p) = 5atm, final volume(v2) = 2.0 Litres(L) ; the workdone, w= not given; the heat, q and q(rev)= not given and the gas was said to expand isothermally.

So, this question is a question from the part of chemistry known as thermodynamics. Therefore, grip yourself we are delving into thermodynamics 'waters' now.

For expansion isothermally; the workdone, w= -nRT ln v2/v1.

Where T= temperature= 25° C = 298 k and R= gas constant.

Therefore; workdone, w = - 1 × 8.314 × 298 × ln(2/1).

Workdone,w= - 1717.32204643. =

- 1717.3 Joules (J).

==> Workdone,w= - 1.7173 kJ.

Then, we are to find q. q can be solved by using the first law of thermodynamics, which by mathematical representation is:

∆U= q + w. Where ∆U= change in internal enegy. Since the question is dealing with isothermal expansion, there is this rule that says for an isothermal expansion ∆U = 0.

Hence, 0 =q + [- 1717.3 Joules (J)].

q=1717.3 J = 1.7173 kJ.

Finally, the q(rev) which is= nRT ln (v2/V1).

q(rev) = 1 × 8.314 × 298 ln (2/1).

q(rev) = 1717.3 J = 1.7173 kJ.

PS: please note the negative signs in the workdone and the positive sign in the q(rev).

7 0
3 years ago
The decomposition of nitrogen dioxide is described by the following chemical equation: Suppose a two-step mechanism is proposed
Mandarinka [93]

Answer:

<u>first step </u>

NO2(g)  ------------------------------------> NO(g) + O(g)

<u>second step</u>

NO2(g) + O(g) -----------------------------> NO(g) + O2(g)

Explanation:

<u>first step </u>

NO2(g)  ------------------------------------> NO(g) + O(g)

<u>second step</u>

NO2(g) + O(g) -----------------------------> NO(g) + O2(g)

8 0
3 years ago
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