Answer:
The answer to your question is P2 = 84.16 kPa
Explanation:
Data
Volume 1 = V1 = 4.52 L Volume 2 = V2 = 4.83 l
Pressure 1 = P1 = 102 kPa Pressure 2 = P2 = ?
Temperature 1 = T1 = 23°C Temperature 2 = T2 = -12°C
Process
1.- Convert the temperature to °K
Temperature 1 = 23 + 273 = 296°K
Temperature 2 = -12 + 273 = 261°K
2.- Use the Combined Gas law to solve this problem
P1V1/T1 = P2V2/T2
-Solve for P2
P2 = P1V1T2 / T1V2
-Substitution
P2 = (102)(4.52)(261) / (296)(4.83)
-Simplification
P2 = 120331.44 / 1429.68
-Result
P2 = 84.16 kPa
26.5 g of Fe₂(SO₄)₃
Explanation:
We have the following chemical reaction:
2 FePO₄ + 3 Na₂SO₄ → Fe₂(SO₄)₃ + 2 Na₃PO₄
number of moles = mass / molecular wight
number of moles of FePO₄ = 20 / 151 = 0.1325 moles
Taking in account the chemical reaction we devise the following reasoning:
if 2 moles of FePO₄ produces 1 mole of Fe₂(SO₄)₃
then 0.1325 moles of FePO₄ produces X moles of Fe₂(SO₄)₃
X = (0.1325 × 1) / 2 = 0.06625 moles of Fe₂(SO₄)₃
mass = number of moles × molecular wight
mass of Fe₂(SO₄)₃ = 0.06625 × 400 = 26.5 g
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number of moles
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Your answer would be carbon dating
Hope this helps