Answer:
% sodium= 13.6 % sodium
% carbon= 35.5 % carbon
% hydrogen= 4.7% hydrogen
% nitrogen = 8.3% nitrogen
% oxygen = 37.8 % oxygen
Explanation:
To find its percent composition means that we are to find to find the percentage of each of the constituents of the compound present.
The molar mass of monosodium glutamate is 169.11 gmol-1
Hence;
Percent of sodium= 23 gmol-1/169.11 gmol-1 × 100 = 13.6 % sodium
Percent of Carbon= 60 gmol-1/169.11 gmol-1 ×100 = 35.5 % carbon
Percent of hydrogen= 8/169.11 gmol-1 ×100 = 4.7% hydrogen
Percent nitrogen = 14/169.11 gmol-1 × 100 = 8.3% nitrogen
Percent oxygen = 64/169.11 gmol-1 ×100 = 37.8 % oxygen
Answer:
36.3
Explanation:
The full answer would be 36.3426, but because of the 0.21, you round it down to 3 sig figs.
For your question about diagram it is definitely A
Answer:
Explanation:
Given that:-
![rate = k[NH_4^+][NO_2^-]](https://tex.z-dn.net/?f=rate%20%3D%20k%5BNH_4%5E%2B%5D%5BNO_2%5E-%5D)
k = 
![[NH_4^+]=0.301\ M](https://tex.z-dn.net/?f=%5BNH_4%5E%2B%5D%3D0.301%5C%20M)
![[NO_2^-]=0.160\ M](https://tex.z-dn.net/?f=%5BNO_2%5E-%5D%3D0.160%5C%20M)
So,
<u>
is the rate of the reaction at that temperature if [NH4+] = 0.301 M and [NO2−] = 0.160 M.</u>
