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3 years ago

Bailey made a pan of cornbread. she cut it into 8 equal pieces and ate 1 piece what fraction of the cornbread did bailey eat

Mathematics

2 answers:

Anestetic [448]3 years ago

8 0

Answer:

1/8

Step-by-step explanation:

You have 8 peices total. She eats one peice, so she ate 1/8 of the cornbread.

Hope this helped! (btw STAN KPOP)

kirill115 [55]3 years ago

7 0

Answer:

1/8

Step-by-step explanation:

Baily has one whole cornbread. that is equal to 8/8. then Baily eats one piece or 8/8 - 1/8 = 7/8

we are asked how many pieces she ate? answer : 1/8

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I need help finding what 875 divided by 46 is ?

Luda [366]

Answer:

19.02173913043478

Step-by-step explanation:

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2 years ago

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If one pound is $4.40 how much is 3/8's of a pound?

baherus [9]

Answer:

1.65

Step-by-step explanation:

you said one pound is $4.40

and that how much is 3/8 of a pound

so 3/8 multiplied by 4.40

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2 years ago

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Suppose that we don't have a formula for g(x) but we know that g(3) = −1 and g'(x) = x2 + 7 for all x.

Sliva [168]

Answer:

g(2.95) ≈ -1.8; g(3.05) ≈ -0.2
A) tangents are increasing in slope, so the tangent is below the curve, and estimates are too small.

Step-by-step explanation:

(a) The linear approximation of g(x) at x=b will be ...

g(x) ≈ g'(b)(x -b) +g(b)

Using the given relations, this is ...

g'(3) = 3² +7 = 16

g(x) ≈ 16(x -3) -1

Then the points of interest are ...

g(2.95) ≈ 16(2.95 -3) -1 = -1.8

g(3.05) ≈ 16(3.05 -3) -1 = -0.2

(b) At x=3, the slope of the curve is increasing, so the tangent lies below the curve. The estimates are too small. (Matches description A.)

4 0

2 years ago

Find the particular solution of the differential equation that satisfies the initial condition(s). f ''(x) = x−3/2, f '(4) = 1,

sweet [91]

Answer:

Hence, the particular solution of the differential equation is $y = \frac{1}{6} \cdot x^{3} - \frac{3}{4}\cdot x^{2} - x$ .

Step-by-step explanation:

This differential equation has separable variable and can be solved by integration. First derivative is now obtained:

$f'' = x - \frac{3}{2}$

$f' = \int {\left(x-\frac{3}{2}\right) } \, dx$

$f' = \int {x} \, dx -\frac{3}{2}\int \, dx$

$f' = \frac{1}{2}\cdot x^{2} - \frac{3}{2}\cdot x + C$ , where C is the integration constant.

The integration constant can be found by using the initial condition for the first derivative ( $f'(4) = 1$ ):

$1 = \frac{1}{2}\cdot 4^{2} - \frac{3}{2}\cdot (4) + C$

$C = 1 - \frac{1}{2}\cdot 4^{2} + \frac{3}{2}\cdot (4)$

$C = -1$

The first derivative is $y' = \frac{1}{2}\cdot x^{2}- \frac{3}{2}\cdot x - 1$ , and the particular solution is found by integrating one more time and using the initial condition ( $f(0) = 0$ ):

$y = \int {\left(\frac{1}{2}\cdot x^{2}-\frac{3}{2}\cdot x -1 \right)} \, dx$

$y = \frac{1}{2}\int {x^{2}} \, dx - \frac{3}{2}\int {x} \, dx - \int \, dx$

$y = \frac{1}{6} \cdot x^{3} - \frac{3}{4}\cdot x^{2} - x + C$

$C = 0 - \frac{1}{6}\cdot 0^{3} + \frac{3}{4}\cdot 0^{2} + 0$

$C = 0$

Hence, the particular solution of the differential equation is $y = \frac{1}{6} \cdot x^{3} - \frac{3}{4}\cdot x^{2} - x$ .

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3 years ago

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laiz [17]

Answer:

(2,10) or x=2 y=10

Step-by-step explanation:

1. Pick one of your equations and solve for a variable. I chose the first equation and solved for x.

5x-2y=-10 (Move the -2y to the other side, you need to do the opposite so you add +2y to -10)

5x=2y-10 (Divide the 5 from the x)

x=2/5y-2

2. Now take what you got for x and plug it into the x variable on the other equation.

3(2/5y-2)+6y=66 (Multiply 3 by 2/5y and -2)

6/5y-6=6y=66 (Move the -6 to the other side and add 6/5y to 6y)

36/5y=72 (Since the number on the y is a fraction, you must do the opposite to the other side)

y=72/1 x 5/36 (Flip your fraction and multiply it by the 72)

y=10

3. Now that you have one of the variables solved for, in order to get the other we must plug in what we have to the first equation.

5x-2(10)=-10 (Multiple 2 by 10)

5x-20=-10 (Move -20 to the other side, since you do the opposite add +20 to the -10)

5x=10 ( Divide 10 by 5)

x= 2

4. If needed, plug in the values of x and y to check your solution.

Hope this could help! :)

3 0

2 years ago