3 years ago

Index of refraction

1 answer:

5 0

Answer:

The relation is n = c/v where c is speed of light in a vacuum....v is the speed of light in the new medium ......n is the refractive index of the material

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The top of lake is frozen as atmospheric temperature is -10 degree Celsius the temperature of the bottom of the lake is most lik

hjlf

4°Celcius Water is densest at 4°C

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4 years ago

What is the acceleration of a 32-kg object is a 6.75-N force is being applied to it?

zimovet [89]

<span>0.21 m/s2

A.)

hope this helps best of luck :)
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3 years ago

With nonreturn to zero signaling, the voltage alternates between zero and a positive or negative voltage. True False

SSSSS [86.1K]

Answer:

False.

Explanation:

No. Voltage does not alternate between zero and positive or negative. In non return signaling (NRZ) voltage at zero represents the 0 bit and at the positive represent the 1 bit. NRZ is one of the signal levels of uni polar Scheme in which the signal does not return to zero at the middle of it. For example 10110. That is why it named as the non return signaling.

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3 years ago

A motor cycle travelling at 10 m/s accelerates at 4m/s for 8s.<br>what is it final velocity?

Vlad1618 [11]

Initial velocity=u=10m/s
Acceleration=a=4m/s^2
Time=t=8s

Final velocity be v

$\\ \bull\tt\longmapsto v=u+at$

$\\ \bull\tt\longmapsto v=10+4(8)$

$\\ \bull\tt\longmapsto v=10+32$

$\\ \bull\tt\longmapsto v=42m/s$

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3 years ago

Read 2 more answers

The same strength force was exerted in the same direction on both Object A and Object B. Why did Object A go faster than Object

VashaNatasha [74]

Answer:

$m_B > m_A$

the mass of body B must be greater than the mass of body A

Explanation:

Newton's second law establishes a linear relationship between the force, the mass of the body and its acceleration

F = m a

a = F / m

Let's analyze this expression tells us that the force is of equal magnitude for the two bodies, but body A goes faster than body B, this implies that it has more relationships

a_A > a_B

$\frac{F}{m_A} > \frac{F}{m_B}$

$m_B > m_A$

Therefore, for this to happen, the mass of body B must be greater than the mass of body A

6 0

3 years ago