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alexandr402 [8]
3 years ago
11

What compound do the ions Al3+ and O2- form

Chemistry
1 answer:
Mars2501 [29]3 years ago
8 0
Hey 

the answer is going to be 

AL3<span> plus and </span>O2<span> negative will </span>form<span> Aluminum Oxide. It has manynames such as corundum and alumina. It is an amphoteric oxide.</span>
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Which statement is true about the cells of non-living objects? A. They have prokaryotic cells. B. They have eukaryotic cells. C.
zloy xaker [14]
D, obviously. All living things are made of one or more cells, therefore non-living things aren’t made of cells
8 0
3 years ago
What are the controlled, independent, and dependent variables of this experiment?
disa [49]

Answer:

controlled: 2 drops of food coloring

independent: temperature of water

dependent: rate of diffusion

Explanation:

A controlled variable doesn't change throughout the whole experiment, a independent variable is something being tested, and a dependent variable is the results

5 0
4 years ago
A 4 gram metal is heated and it's temperature changes from 25 degrees C to 35
mote1985 [20]

Answer:

O60J

Explanation:

6 0
3 years ago
Read 2 more answers
How many grams of Ag2S2O3 form
Art [367]

Taking into account the reaction stoichiometry, 109.09 grams of Ag₂S₂O₃ are formed when 125 g AgBr reacts completely.

<h3>Reaction stoichiometry</h3>

In first place, the balanced reaction is:

2 AgBr + Na₂S₂O₃ → Ag₂S₂O₃ + 2 NaBr

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

  • AgBr: 2 moles
  • Na₂S₂O₃: 1 mole
  • Ag₂S₂O₃: 1 mole
  • NaBr: 2 moles

The molar mass of the compounds is:

  • AgBr: 187.77 g/mole
  • Na₂S₂O₃: 158 g/mole
  • Ag₂S₂O₃: 327.74 g/mole
  • NaBr: 102.9 g/mole

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

  • AgBr: 2 moles ×187.77 g/mole= 375.54 grams
  • Na₂S₂O₃: 1 mole ×158 g/mole= 158 grams
  • Ag₂S₂O₃: 1 mole ×327.74 g/mole= 327.74 grams
  • NaBr: 2 moles ×102.9 g/mole= 205.8 grams

<h3>Mass of Ag₂S₂O₃ formed</h3>

The following rule of three can be applied: if by reaction stoichiometry 375.54 grams of AgBr form 327.74 grams of Ag₂S₂O₃, 125 grams of AgBr form how much mass of Ag₂S₂O₃?

mass of Ag_{2} S_{2} O_{3} =\frac{125 grams of AgBrx327.74 grams of Ag_{2} S_{2} O_{3}}{375.54 grams of AgBr}

<u><em>mass of Ag₂S₂O₃= 109.09 grams</em></u>

Then, 109.09 grams of Ag₂S₂O₃ are formed when 125 g AgBr reacts completely.

Learn more about the reaction stoichiometry:

brainly.com/question/24741074

brainly.com/question/24653699

#SPJ1

4 0
2 years ago
Do anyone know how to do question B
Over [174]

Answer:

a) IUPAC Names:

                   1) (<em>trans</em>)-but-2-ene

                   2) (<em>cis</em>)-but-2-ene

                   3) but-1-ene

b) Balance Equation:

                       C₄H₁₀O + H₃PO₄   →   C₄H₈ + H₂O + H₃PO₄

As H₃PO₄ is catalyst and remains unchanged so we can also write as,

                                    C₄H₁₀O   →   C₄H₈ + H₂O

c) Rule:

           When more than one alkene products are possible then the one thermodynamically stable is favored. Thermodynamically more substituted alkenes are stable. Furthermore, trans alkenes are more stable than cis alkenes. Hence, in our case the major product is trans alkene followed by cis. The minor alkene is the 1-butene as it is less substituted.

d) C is not Geometrical Isomer:

        For any alkene to demonstrate geometrical isomerism it is important that there must be two different geminal substituents attached to both carbon atoms. In 1-butene one carbon has same geminal substituents (i.e H atoms). Hence, it can not give geometrical isomers.

7 0
3 years ago
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