Two terminal device which can maintain a fixed voltage. Hope this help I need more detail in your question this is all I can provide. :)
Answer:
Explanation:
Given:
Length of a rope,
Position of Canary on the rope from one end,
Position of Grackle on the rope from another end,
Tension in the rope,
linear mass distribution on the rope,
We have for the speed of wave on the string:
<em>For canary to be undisturbed we need a node at this location.</em>
<em>Also, at the end close to Canary there must be a node to avoid any change in pattern of vibration.</em>
So,
the distance between Canary and the closer end must be equal to half the wavelength.
∴Wavelength of wave to be produced = 20 m. This will give us nodes at the multiples of 10 and anti-nodes at the multiples of 5.
Now, frequency:
Answer:
the kinetic energy of clown A is 0.444 times the kinetic energy of clown B.
Explanation:
Let the spring constant of the spring is k.
For clown A:
m = 40 kg
let the extension in the spring is y.
So, the spring force, F = k y
m g = k y
40 x g = k x y
y = 40 x g / k ..... (1)
For clown B:
m' = 60 kg
Let the extension in the spring is y'.
So, the spring force, F' = k y'
m' g = k y'
y' = 60 x g / k .....(2)
Kinetic energy for A, K = 1/2 ky^2
Kinetic energy for B, K' = 1/2 ky'^2
So, K/K' = y^2/y'^2 K / K' = (40 x 40) / (60 x 60) (from equation (1) and (2))
K / K' = 0.444
K = 0.444 K'
So the kinetic energy of clown A is 0.444 times the kinetic energy of clown B.
The nucleus of an atom is about 10-15 m in size; this means it is about 10-5 (or 1/100,000) of the size of the whole atom. A good comparison of the nucleus to the atom is like a pea in the middle of a racetrack. (10-15 m is typical for the smaller nuclei; larger ones go up to about 10 times that.)