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Lisa [10]
3 years ago
6

What force is required to accelerate to 10 kg object to 5.9 m/s/s?

Physics
1 answer:
g100num [7]3 years ago
3 0

Force required to accelerate 10 kg object to 5.9 m/s/s ?

Mass = 10 kg

Acceleration = 5.9 m/s^2

Force = Mass * Acceleration

Force = 10 kg * 5.9 m/s^2

Force = 59 kg m /s^2 = 59 N

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The position of a particle moving along the x axis is given by x = (21 + 22t – 6 t2) m, where t is in s. What is the average vel
romanna [79]

Answer:

12m/s

Explanation:

x = (21 + 22t – 6 t2) m,

We can express change bin velocity as

dx/dt= -12t + 22

But Velocity is changing

interval t = 1 s

t = 4 s

at t = 1, x = 21 + 22(1) -6(1)^2

=37

at t = 4, x = 21 + 22(4) -6(4)^2

=13

Distance travelled at interval t = 1 s

t = 4 s

X2 - X1=13- 37. = - 24m

Velocity= displacement/ time

= 24/(3-1)=12 m/s

7 0
3 years ago
Ms. Senko is moving a desk around her classroom, the desk weighs 125N.
Lana71 [14]

Answer:

Static force of friction = 428.75 N

Kinetic Force of Friction = 281.75 N

Explanation:

The static force of friction is equal to Coefficient of static Friction * Mass * g

= 0.35 *125 * 9.8

= 428.75 N

The Kinetic force of friction is equal to Coefficient of kinetic Friction * Mass * g

= 0.23 *125 * 9.8

= 281.75 N

6 0
2 years ago
the distance between 2 station is 5400 m find the time taken by a train to cover this distance, if the train travels with speed
iragen [17]

Answer:

I dont know bro

Explanation:

Ask an expert

8 0
3 years ago
Read 2 more answers
Boyle’s Law states that when a sample of gas is compressed at a constant temperature, the pressure P of the gas is inversely pro
jolli1 [7]

Answer:

a)V=\dfrac{5.3}{P}

b)ML^{-4}T^{-2}.

Explanation:

Given that

Boyle's law

P V = Constant ,at constant temperature

a)

Given that

P_1=50KPa

V_1=0.106m^3

We know that for PV=C

P_1V_1=P_2V_2=PV

Now by putting the values

PV= 50 x 0.106

V=\dfrac{5.3}{P}

Where P is in KPa and V is in m^3

b)

PV= C

Take ln both sides

So \ln(PV)=\ln C

lnP + lnV =lnC               ( C is constant)

By differentiating

\dfrac{dP}{P}+\dfrac{dV}{V}=0

So

\dfrac{dP}{dV}=-\dfrac{P}{V}

When P= 50 KPa

\dfrac{dP}{dV}=-\dfrac{50}{V}\ \dfrac{KPa}{m^3}

It indicates the slope of PV=C curve.

It unit is \dfrac{Pa}{m^3}.

Or we can say that ML^{-4}T^{-2}.

5 0
3 years ago
Read 2 more answers
A ball of mass is released from rest at a height of 30 how fast is it going when it hits the ground
elena55 [62]

Answer:

If the height is in metres, the speed is 24.25m/s

7 0
3 years ago
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