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ArbitrLikvidat [17]

3 years ago

7

Let f(x)=4x+9. Write a function g whose graph is a reflection in the y-axis of the graph of f. g(x)= ?

1 answer:

frez [133]3 years ago

3 0

Answer:

$g(x)=-4x+9$

Step-by-step explanation:

So we know that:

$f(x)=4x+9$

To reflect across the <em>y-axis</em>, instead of x, use -x. Therefore:

$g(x)=f(-x)=4(-x)+9$

Simplify:

$g(x)=-4x+9$

And that's our answer :)

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Suppose a car is traveling at 60 km/hr, and that the positive y-axis is north and the positive x-axis is east. Resolve the car's

levacccp [35]

For the answer to the question above asking to r<span>esolve the car's velocity vector (in 2-space) into components if the car is traveling in each of the following directions. The units are km/hr, but
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<span>SE: (30√2)i - (30√2)j </span>
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6 0

2 years ago

Tom bought 2.1 pounds of each type of fruit shown on the sign. What was the total cost of the fruit he brought.

Artist 52 [7]

Answer:

Can I see the sign?

Step-by-step explanation:

5 0

3 years ago

I NEED HELP ASAPPP!!!! It’s urgentttttt!!!!

Akimi4 [234]

Answer: (x - 2)² + (y - 14)² = 1

Step-by-step explanation:

<u>Concept:</u>

Here, we need to know the idea of the circle formula.

Circle formula: (x - h)² + (y - k)² = r²

Center = (h, k)

Radius = r

If you are still confused, please refer to the attachment below for a graphical explanation.

<u>Solve:</u>

Center = (2, 14)

Radius = 1

<em>Given formula</em>

(x - h)² + (y - k)² = r²

<em>Substitute the value into the formula</em>

(x - 2)² + (y - 14)² = (1)²

<em>Simplify</em>

(x - 2)² + (y - 14)² = 1

Hope this helps!! :)

Please let me know if you have any questions

8 0

3 years ago

If the median were to be calculated at 82.5 degrees, then would the feasible mean be 81.6?

dmitriy555 [2]

I think your right,It would be 81.6.
Hope this helps. :D

7 0

3 years ago

In Exercises 10 and 11, points B and D are points of tangency. Find the value(s) of x.<br>

Lemur [1.5K]

In both cases,

$AB^2=AD^2$

(as a consequence of the interesecting secant-tangent theorem)

So we have

10.

$(4x+7)^2=(6x-3)^2$

$16x^2+56x+49=36x^2-36x+9$

$20x^2-92x-40=0$

$5x^2-23x-10=0$

$(5x+2)(x-5)=0\implies\boxed{x=5}$

(omit the negative solution because that would make at least one of AB or AD have negative length)

11.

$(4x^2-18x-10)^2=(x^2+x+4)^2$

$16x^4-144x^3+244x^2+360x+100=x^4+2x^3+9x^2+8x+16$

$15x^4-146x^3+235x^2+352x+84=0$

$(x-7)(3x+2)(5x^2-17x-6)=0\implies\boxed{x=-\dfrac23\text{ or }x=7}$

(again, omit the solutions that would give a negative length for either AB or AD)

7 0

3 years ago