Answer:
18.94%.
Explanation:
- The decay of carbon-14 is a first order reaction.
- The rate constant of the reaction (k) in a first order reaction = ln (2)/half-life = 0.693/(5730 year) = 1.21 x 10⁻⁴ year⁻¹.
- The integration law of a first order reaction is:
<em>kt = ln [A₀]/[A]</em>
k is the rate constant = 1.21 x 10⁻⁴ year⁻¹.
t is the time = 13,750 years.
[A₀] is the initial percentage of carbon-14 = 100.0 %.
[A] is the remaining percentage of carbon-14 = ??? %.
∵ kt = ln [Ao]/[A]
∴ (1.21 x 10⁻⁴ year⁻¹)(13,750 years) = ln (100.0%)/[A]
1.664 = ln (100.0%)/[A]
Taking exponential for both sides:
5.279 = (100.0%)/[A]
<em>∴ [A]</em> = (100.0%)/5.279 = <em>18.94%.</em>
The energy of the photon from the calculation performed is 3.5 * 10^-16 J.
<h3>What is a photon?</h3>
A photon is a packet of light. It was derived from the theory of Albert Einstein. The energy of a photon is obtained from; E = hc/λ
- h= Plank's constant
- c = speed of light
- λ = wavelength
Now we have that;
E = 6.6 * 10^-34 * 3 * 10^8/562 * 10^-9
E = 3.5 * 10^-16 J
Missing parts:
Calculate the energy, in joules, of a photon of green light having a wavelength of 562nm?
Learn more about energy of photon:brainly.com/question/20912241
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I think it's calorie
Hope this helps
