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8090 [49]
3 years ago
11

SELECT ALL THAT APPLY

Chemistry
2 answers:
Scilla [17]3 years ago
3 0
At STP conditions, 0.25 moles of CO2(g), H2(g), NH3(g)

The answers are:
<span>1. Will contain the same number of molecules </span>
3. Will occupy the same volume

koban [17]3 years ago
3 0

<u>Answer:</u> The correct answer is Option 1 and Option 3.

<u>Explanation:</u>

We are given:

0.25 moles of CO_2,H_2\text{ and }NH_3

STP conditions states that 1 mole of a gas occupies 22.4 L of volume.

The volume occupied by all the gases at STP will be 0.25\times 22.4=5.6L

According to mole concept: 1 mole of a compound contains 6.022\times 10^{23} number of molecules or 1 mole of an element contains 6.022\times 10^{23} number of atoms.

We know that the given gases are compounds. Thus, all the three gases will have 0.25\times 6.022\times 10^{23}=1.5055\times 10^{23} number of molecules.

Hence, the correct answer is Option 1 and Option 3.

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Therefore, the object and description that matches is Object 2 and T.

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6 0
2 years ago
Read 2 more answers
What would be the result on the Insect population if the Bats and Mice were removed?
Ivanshal [37]

Answer:

We wouldn't have Coronavirus

Explanation:

5 0
2 years ago
For which of the following activities might you want to hire a chemist?
worty [1.4K]

For which of the following activities might you want to hire a chemist?

Answer: D. testing a rock sample for gold content

Which of the following procedures involves a physical change in one of the substances?

Answer: C. separating a salt solution by evaporating the water

7 0
2 years ago
Read 2 more answers
8.43g of CaCl2·2H2O is dissolved in 40.0g of H2O. What is the molality of the solution? (Note that the H2O in the CaCl2·2H2O mus
lara31 [8.8K]

Answer:

[CaCl₂·2H₂O] = 1.43 m

Explanation:

Molality is mol of solute / kg of solvent.

Mass of solvent = 40 g

Let's convert g to kg → 40 g / 1000 = 0.04 kg

Let's determine the moles of solute (mass / molar mass)

8.43 g / 146.98 g/mol = 0.057 mol

Molality = 0.057 mol / 0.04 kg → 1.43

3 0
3 years ago
Read 2 more answers
A mixture of carbon dioxide and helium gases is maintained in a 7.91 L flask at a pressure of 1.42 atm and a temperature of 33 °
Crank

Answer:

The gas mixture contains 1.038 grams of helium

Explanation:

<u>Step 1:</u> Data given

Volume of the flask = 7.91 L

Total Pressure = 1.42 atm

Temperature = 33 °C

Mass of CO2 = 8.25 grams

Molar mass of CO2 = 44.01 g/mol

Molar mass of He = 4 g/mol

<u>Step 2</u>: Calculate total number moles of gas

p*V = n*R*T

⇒ p = the pressure = 1.42 atm

⇒ V = the volume = 7.91 L

⇒ n= the number of moles = TO BE DETERMINED

⇒ R = the gas constant = 0.08206 L* atm/K*mol

⇒ T = the temperature = 33 °C = 306 Kelvin

n = (p*V)/(R*T)

n = (1.42*7.91)/(0.08206 * 306)

n = 0.447 moles

<u>Step 3</u>: Calculate moles of CO2

Moles CO2 = mass CO2 / Molar mass CO2

Moles CO2 = 8.25 grams / 44.01 g/mol

Moles CO2 = 0.1875 moles

<u>Step 4:</u> Calculate moles of Helium

Moles Helium = total moles of gas - moles of CO2

Moles Helium = 0.447 - 0.1875 = 0.2595 moles of helium

<u>Step 5: </u> Calculate mass of helium

Mass of helium = moles of helium * molar mass of helium

Mass of helium = 0.2595 moles * 4 g/mol

Mass of helium = 1.038 grams

The gas mixture contains 1.038 grams of helium

8 0
2 years ago
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