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Colt1911 [192]
3 years ago
6

What class of organic product results when 1-heptyne is treated with a mixture of mercuric acetate (HgSO4) in aqueous sulfuric a

cid (H2O/H2SO4)

Chemistry
1 answer:
Alekssandra [29.7K]3 years ago
7 0

Answer:

<u>heptan-2-one</u>

Explanation:

In this case, the final product would be a ketone: <u>heptan-2-one</u>. To understand why this molecule is produced we have to check the<u> reaction mechanism</u>.

The first step is the <u>protonation</u> of the triple bond to produce the more stable carbocation (a secondary one) by the action of sulfuric acid H_2SO_4. The next step is the <u>attack of water</u> to the carbocation to produce a new bond between C and the O, producing a positive charge in the oxygen. Then, a <u>deprotonation</u> step takes place to produce an <u>enol</u>. Finally, we will have a rearrangement (<u>keto-enol tautomerism</u>) to produce the final ketone.

See figure 1

I hope it helps!

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The gravitational force acting on an object is also called the object's _____. A) mass B) weight C) density D) volume​
Veseljchak [2.6K]

Answer:

B) weight

Thats it no explanation

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What is the Noble gas notation for mercury (Hg)?.
lapo4ka [179]
The noble gas notation of an element includes a noble gas as a condensed way to describe the electronic configuration of an element. IN this case, the nearest noble gas is xenon with an atomic number of 54. Hg's atomic number is 80 so we need 26 more. In this case, after [Xe], the configuration starts with 6s². Hence to complete the configuration the answer is  [Xe] 6s2  4f14 5d10
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What does a graph with no trend indicate about the variables?
Alborosie
If the graph has no trend which means almost constant, it indicates that the dependent variables will not change when the independent variables change.
8 0
4 years ago
A certain half-reaction has a standard reduction potential E0red = +0.13V . An engineer proposes using this half-reaction at the
Ivan

Answer:

a. 1.23 V

b. No maximum

Explanation:

Required:

a. Is there a minimum standard reduction potential that the half-reaction used at the cathode of this cell can have?

b. Is there a maximum standard reduction potential that the half-reaction used at the cathode of this cell can have?

The standard cell potential (E°cell) is the difference between the standard reduction potential of the cathode and the standard reduction potential of the anode.

E°cell = E°red, cat - E°red, an

If E°cell must be at least 1.10 V (E°cell > 1.10 V),

E°red, cat - E°red, an > 1.10 V

E°red, cat - 0.13V > 1.10 V

E°red, cat > 1.23 V

The minimum standard reduction potential is 1.23 V while there is no maximum standard reduction potential.

4 0
3 years ago
The substance fluorine has the following properties: normal melting point: 53.5 K normal boiling point: 85.0 K triple point: 1.6
mihalych1998 [28]

Answer:

The true statements include;

- The sample is initially a gas.

- The final state of the substance is a solid.

- One or more phase changes will occur.

The untrue/false statements include;

- The liquid initially present will vaporize.

- The final state of the substance is a liquid.

Explanation:

A couple pieces of informatton on Fluorine is imitially provided.

The substance fluorine has the following properties: normal melting point: 53.5 K normal boiling point: 85.0 K triple point: 1.6×10-4 atm, 53.4 K critical point: 55 atm, 144.1 K

So, a question is now attached about a sample of Fluorine. A sample of fluorine at a pressure of 1.00 atm and a temperature of 90.3 K is cooled at constant pressure to a temperature of 49.3 K.

We are then told to examine a group of options to find the ones that are correct/apply.

Taking the options one at a time

- The sample is initially a gas.

The initial state of the Fluorine sample has its temperature at 90.3 K, which is above the gas' boiling point. Hence, the sample can be concluded to initially be a gas.

- The liquid initially present will vaporize.

The sample doesn't initially contain liquid. And even of it did, the temperature is cooled, not heated , Hence, this statement is wrong.

- The final state of the substance is a solid.

The sample of Fluorine moves from a temperature higher than boiling point (85.0 K), with the sample in gaseous form, to one that is at a lower temperature (49.3 K) than the gas' normal melting point (53.5 K).

At temperatures lower than melting point, a substance exists in the solid form. Hence, this statement is true. The final state of the substance is solid.

- One or more phase changes will occur.

In moving from 90.3 K to 49.3 K for the sample and passing through the substance's boiling and melting points (85.0 K and 53.5 K respectively) along the way, it is logical to conclude that there would be one or more phase changes will occur. This statement is true.

- The final state of the substance is a liquid.

This is false as we already established that the final state of the substance is a solid. Hence, this statement is false.

Hope this Helps!!!

7 0
4 years ago
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